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An urn contains 8 white, 6 blue, and 9 red balls. How many ways can 6 balls be selected to meet each condition? A) Three balls are blue, 2 are white, and 1 is red. B) Two are blue, and 4 are red.

Mathematics
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use random variables
http://mathforum.org/library/drmath/view/69151.html

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Other answers:

lol, the other site thing is confusing..
hold on one second
ok 3 blue 2 white 1 red \[\dbinom{6}{3}\dbinom{8}{2}\dbinom{9}{1}\] is it clear how to compute these?
Yes. Now?
Wait..so you just divide then multiply? Which results in 72?

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