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GOODMAN

  • 4 years ago

An urn contains 8 white, 6 blue, and 9 red balls. How many ways can 6 balls be selected to meet each condition? A) Three balls are blue, 2 are white, and 1 is red. B) Two are blue, and 4 are red.

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  1. DHASHNI
    • 4 years ago
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    use random variables

  2. Mathisnotfun
    • 4 years ago
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    http://mathforum.org/library/drmath/view/69151.html

  3. imranmeah91
    • 4 years ago
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    paging @satellite73

  4. GOODMAN
    • 4 years ago
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    lol, the other site thing is confusing..

  5. anonymous
    • 4 years ago
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    hold on one second

  6. anonymous
    • 4 years ago
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    ok 3 blue 2 white 1 red \[\dbinom{6}{3}\dbinom{8}{2}\dbinom{9}{1}\] is it clear how to compute these?

  7. GOODMAN
    • 4 years ago
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    Yes. Now?

  8. GOODMAN
    • 4 years ago
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    Wait..so you just divide then multiply? Which results in 72?

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