Question Of The Day.

- anonymous

Question Of The Day.

- katieb

See more answers at brainly.com

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

Prove that 1 = 2 , 0 = 1 and 1 = 2. I need clever answers.

- anonymous

not this one again D:
algbebraic expressions is my final answer

- anonymous

algebraic*

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

All are requested to try. This is a puzzle question.

- anonymous

O + 4 = 5. solve for ooh.

- Callisto

x = 2x
Cross out x -> 1=2 :S

- lgbasallote

Let a= b
Then a^2 = ab
a^2 + a^2 = a^2 + ab
2a^2 = a^2 + ab
2a^2 - 2ab = a^2 + ab - 2ab
2a^2 - 2ab = a^2 - ab
2(a^2 - ab) = a^2 - ab
--------- -------
a^2 - ab a^2 - ab
2 = 1

- anonymous

U can answer in so many ways. Try all.

- anonymous

whoa...I'm keeping my bf

- anonymous

x + x = 4x
x(1+1) = 4x
(1 + 1) = 4
2 = 4
1 = 2

- anonymous

@lgbasallote answer is thrilling. I was searching for ur answer, LGBA!!!!! Now proceed and u can solve that 1=0 and also 0 = 2.

- lgbasallote

it's actually a fallacy lol =)) dividing 0 by 0 is illegal :p

- anonymous

@Aadarsh: This is not a puzzle, this is wrong mathematics. Finding the error would be some fun though.

- anonymous

Everything is possible in maths, lgba.

- anonymous

dividing by 0 is a fantasy?

- anonymous

Its fun time guys and girls. Lets enjoy

- anonymous

stuff just got real.

- anonymous

aad plzz aye koi question hai ..........

- Callisto

@ffm true, we cannot cancel the variables like that :P

- apoorvk

let x=0
then 20x = 100x
or x = 5x
or 1 = 5
:P :p
Okayy... proving is one thing. I ll ask you guys this: wherein here is the trouble. Which step did we make the mistake at, so we get such erratic answers that would cause Newton to suffer a heart attack if he ever saw this? ;)

- anonymous

@apoorvk smart reply. Newton would have given us gifts!!!!!

- apoorvk

oh yeah @foolformath already asked this. so where is the error, aadarsh can you think? (this question was presented in Bansal classes entrance test multiple times)

- lgbasallote

@Callisto how do you tag @FoolForMath with ffm???

- apoorvk

like this @ffm

- anonymous

Really? Bansal people are copying from Brain Mapping Academy, Hyderabad.

- apoorvk

:D sorry for the troubles FFM

- lgbasallote

i dont think @ffm is the same as @FoolForMath yes?

- anonymous

I am not notified with @ffm

- apoorvk

may be, aadarsh. or the other way around. someone always copies from somebody

- anonymous

@Mani_Jha , @AravindG , @payalvsangle , @heena , @sheena101 , @gurvinder , @Ishaan94 , please try. I have to present this before my seniors and get cash prize.

- Callisto

Hmmm... I was trying to show that I was responding his words, so .... it doesn't matter if I have really tagged him :P

- apoorvk

So, Aadarsh where is the trouble. try guessing!

- anonymous

@apoorvk bhai, there is no mistake. Mistake der in assumption.

- lgbasallote

the fallacy works well

- Mani_Jha

@As a general rule, you shouldn't multiply or divide an equation by zero.

- anonymous

let x=0
then 20x = 100x
or x = 5x
or 1 = 5 (How are you cancelling x? This is division by zero)

- Mani_Jha

(1âˆ’2)^2=(2âˆ’1)^2=1
1âˆ’2=2âˆ’1
2=4
1=2
Find out the mistake in this.

- anonymous

Mistake is in this: 1-2 = 2-1

- KingGeorge

How about a proof that shows \(e=1\)?
\[\Large e=e^{2\pi i \over 2\pi i}=(e^{2\pi i})^{1 \over 2 \pi i}=1^{1 \over 2 \pi i}=1\]

- anonymous

Hats off to @KingGeorge .

- Mani_Jha

Haha. Good. I used a fallacy to prove another fallacy!

- anonymous

\(a^2 = b^2 \implies \pm a= \pm b \) So there are two solutions.

- Mani_Jha

@KingGeorge, finding the value of anything to a complex power doesn't make sense.
You can't be sure that:
\[1^{1/2\pi i}=1\]

- KingGeorge

An alternative proof I found online:
Let \(2e=f\). Then \(2^{2 \pi i}e^{2 \pi i} =f^{2\pi i}\). Since \(e^{2\pi i}=1\), we know that \(2^{2\pi i}=f^{2\pi i}\). This means that \(2=f\). From that we substitute \(f\) back in, and get \[2e=2\]Thus, \(e=1\)

- anonymous

@KingGeorge: When a number is raised to a complex power, the result is not precisely defined.

- anonymous

See here: http://en.wikipedia.org/wiki/Mathematical_fallacy.

- KingGeorge

It's the basically the same deal for the second one. \(f^{2\pi i}\) can get really funky. \(2^{2\pi i}\) is already funky.

- apoorvk

exactly. there is a mistake as @ffm just showed. how do you think are you dividing by '0'??

- anonymous

Can we not try to prove that division by zero is indeed possible? At least by this, we can get the Abel Prize.

- apoorvk

Abel prize. lol

- apoorvk

you 'll get special academic razzies for that!

- anonymous

Lets hope so!!!!!!!!!!!!!!!!!!!!!!!

- KingGeorge

@Mani_Jha The actual problem with my original proof is that \[\Large e^{{2 \pi i} \over {2 \pi i}} \neq (e^{2 \pi i})^{1 \over {2 \pi i}}\]Complex exponents don't do that.

- Mani_Jha

@Aadarsh, You can't do that. That's why zero is called the 'hero' of Mathematics!

- anonymous

Oooooo! Really??

- anonymous

@shruti , @PRINCEOFPERSIA please try.

- anonymous

tumne apne info mei ye sab kya likh dala hai?

- anonymous

Mera naam hai didi!!!!!! Yeh to maine dhamaal se copy kiya hai.!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

- anonymous

cool...yhi kaam kro aur ye kya qestn post kar rakha hai. i felt sumth imp. is there but is'nt

- anonymous

Multiply zero on both sides.
1 x 0 = 2 x 0
0 = 0
1 = 2

- anonymous

Smart answer, Prince Bhai.

- anonymous

Thanks @ Aadarsh..

- experimentX

1 = 1
1^0 = 2^0 = 3^0 = a^0
1 = 2 = 3 = a

Looking for something else?

Not the answer you are looking for? Search for more explanations.