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Aadarsh
 3 years ago
Question Of The Day.
Aadarsh
 3 years ago
Question Of The Day.

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Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1Prove that 1 = 2 , 0 = 1 and 1 = 2. I need clever answers.

rebeccaskell94
 3 years ago
Best ResponseYou've already chosen the best response.0not this one again D: algbebraic expressions is my final answer

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1All are requested to try. This is a puzzle question.

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.0O + 4 = 5. solve for ooh.

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.1x = 2x Cross out x > 1=2 :S

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0Let a= b Then a^2 = ab a^2 + a^2 = a^2 + ab 2a^2 = a^2 + ab 2a^2  2ab = a^2 + ab  2ab 2a^2  2ab = a^2  ab 2(a^2  ab) = a^2  ab   a^2  ab a^2  ab 2 = 1

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1U can answer in so many ways. Try all.

rebeccaskell94
 3 years ago
Best ResponseYou've already chosen the best response.0whoa...I'm keeping my bf

Mathisnotfun
 3 years ago
Best ResponseYou've already chosen the best response.0x + x = 4x x(1+1) = 4x (1 + 1) = 4 2 = 4 1 = 2

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1@lgbasallote answer is thrilling. I was searching for ur answer, LGBA!!!!! Now proceed and u can solve that 1=0 and also 0 = 2.

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0it's actually a fallacy lol =)) dividing 0 by 0 is illegal :p

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.6@Aadarsh: This is not a puzzle, this is wrong mathematics. Finding the error would be some fun though.

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1Everything is possible in maths, lgba.

dpaInc
 3 years ago
Best ResponseYou've already chosen the best response.0dividing by 0 is a fantasy?

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1Its fun time guys and girls. Lets enjoy

rebeccaskell94
 3 years ago
Best ResponseYou've already chosen the best response.0stuff just got real.

gurvinder
 3 years ago
Best ResponseYou've already chosen the best response.0aad plzz aye koi question hai ..........

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.1@ffm true, we cannot cancel the variables like that :P

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.1let x=0 then 20x = 100x or x = 5x or 1 = 5 :P :p Okayy... proving is one thing. I ll ask you guys this: wherein here is the trouble. Which step did we make the mistake at, so we get such erratic answers that would cause Newton to suffer a heart attack if he ever saw this? ;)

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1@apoorvk smart reply. Newton would have given us gifts!!!!!

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.1oh yeah @foolformath already asked this. so where is the error, aadarsh can you think? (this question was presented in Bansal classes entrance test multiple times)

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0@Callisto how do you tag @FoolForMath with ffm???

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1Really? Bansal people are copying from Brain Mapping Academy, Hyderabad.

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.1:D sorry for the troubles FFM

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0i dont think @ffm is the same as @FoolForMath yes?

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.6I am not notified with @ffm

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.1may be, aadarsh. or the other way around. someone always copies from somebody

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1@Mani_Jha , @AravindG , @payalvsangle , @heena , @sheena101 , @gurvinder , @Ishaan94 , please try. I have to present this before my seniors and get cash prize.

Callisto
 3 years ago
Best ResponseYou've already chosen the best response.1Hmmm... I was trying to show that I was responding his words, so .... it doesn't matter if I have really tagged him :P

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.1So, Aadarsh where is the trouble. try guessing!

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1@apoorvk bhai, there is no mistake. Mistake der in assumption.

lgbasallote
 3 years ago
Best ResponseYou've already chosen the best response.0the fallacy works well

Mani_Jha
 3 years ago
Best ResponseYou've already chosen the best response.0@As a general rule, you shouldn't multiply or divide an equation by zero.

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.6let x=0 then 20x = 100x or x = 5x or 1 = 5 (How are you cancelling x? This is division by zero)

Mani_Jha
 3 years ago
Best ResponseYou've already chosen the best response.0(1−2)^2=(2−1)^2=1 1−2=2−1 2=4 1=2 Find out the mistake in this.

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1Mistake is in this: 12 = 21

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1How about a proof that shows \(e=1\)? \[\Large e=e^{2\pi i \over 2\pi i}=(e^{2\pi i})^{1 \over 2 \pi i}=1^{1 \over 2 \pi i}=1\]

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1Hats off to @KingGeorge .

Mani_Jha
 3 years ago
Best ResponseYou've already chosen the best response.0Haha. Good. I used a fallacy to prove another fallacy!

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1@King , @shruti , @neha2050 , @salini Please try.

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.6\(a^2 = b^2 \implies \pm a= \pm b \) So there are two solutions.

Mani_Jha
 3 years ago
Best ResponseYou've already chosen the best response.0@KingGeorge, finding the value of anything to a complex power doesn't make sense. You can't be sure that: \[1^{1/2\pi i}=1\]

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1An alternative proof I found online: Let \(2e=f\). Then \(2^{2 \pi i}e^{2 \pi i} =f^{2\pi i}\). Since \(e^{2\pi i}=1\), we know that \(2^{2\pi i}=f^{2\pi i}\). This means that \(2=f\). From that we substitute \(f\) back in, and get \[2e=2\]Thus, \(e=1\)

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.6@KingGeorge: When a number is raised to a complex power, the result is not precisely defined.

FoolForMath
 3 years ago
Best ResponseYou've already chosen the best response.6See here: http://en.wikipedia.org/wiki/Mathematical_fallacy.

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1It's the basically the same deal for the second one. \(f^{2\pi i}\) can get really funky. \(2^{2\pi i}\) is already funky.

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.1exactly. there is a mistake as @ffm just showed. how do you think are you dividing by '0'??

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1Can we not try to prove that division by zero is indeed possible? At least by this, we can get the Abel Prize.

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.1you 'll get special academic razzies for that!

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1Lets hope so!!!!!!!!!!!!!!!!!!!!!!!

KingGeorge
 3 years ago
Best ResponseYou've already chosen the best response.1@Mani_Jha The actual problem with my original proof is that \[\Large e^{{2 \pi i} \over {2 \pi i}} \neq (e^{2 \pi i})^{1 \over {2 \pi i}}\]Complex exponents don't do that.

Mani_Jha
 3 years ago
Best ResponseYou've already chosen the best response.0@Aadarsh, You can't do that. That's why zero is called the 'hero' of Mathematics!

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1@shruti , @PRINCEOFPERSIA please try.

shruti
 3 years ago
Best ResponseYou've already chosen the best response.0tumne apne info mei ye sab kya likh dala hai?

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1Mera naam hai didi!!!!!! Yeh to maine dhamaal se copy kiya hai.!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

shruti
 3 years ago
Best ResponseYou've already chosen the best response.0cool...yhi kaam kro aur ye kya qestn post kar rakha hai. i felt sumth imp. is there but is'nt

PRINCEOFPERSIA
 3 years ago
Best ResponseYou've already chosen the best response.0Multiply zero on both sides. 1 x 0 = 2 x 0 0 = 0 1 = 2

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.1Smart answer, Prince Bhai.

PRINCEOFPERSIA
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks @ Aadarsh..

experimentX
 3 years ago
Best ResponseYou've already chosen the best response.01 = 1 1^0 = 2^0 = 3^0 = a^0 1 = 2 = 3 = a
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