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jatinbansalhot
Group Title
find out the limit of the following
( sin x ) / x where x > 0
 2 years ago
 2 years ago
jatinbansalhot Group Title
find out the limit of the following ( sin x ) / x where x > 0
 2 years ago
 2 years ago

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jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
plz explain too . i found out it to be 0. u r right it is 1 how
 2 years ago

furan143 Group TitleBest ResponseYou've already chosen the best response.1
answer is 1,actually it's proof is a bit theoretical .if you want any proof please refer some standard text
 2 years ago

furan143 Group TitleBest ResponseYou've already chosen the best response.1
it's proof is well known and is known as sandwich theorem
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
as x reduces, the sin of x also reduces, then why 1
 2 years ago

ankit709 Group TitleBest ResponseYou've already chosen the best response.0
if u put the value of limit then u will get 0/0 form
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
i will get 0
 2 years ago

furan143 Group TitleBest ResponseYou've already chosen the best response.1
offcourse buddy
 2 years ago

ankit709 Group TitleBest ResponseYou've already chosen the best response.0
u can apply dy/dx
 2 years ago

furan143 Group TitleBest ResponseYou've already chosen the best response.1
actually 0/0 is a indeterminate value
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
derivative ? but i don't know the derivative i'm beginner but soon be older :D :D hahahaa
 2 years ago

ankit709 Group TitleBest ResponseYou've already chosen the best response.0
this is L hospital rule
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
furan.. yah that would be indeterminate state
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
ohhh.. hospital ....
 2 years ago

furan143 Group TitleBest ResponseYou've already chosen the best response.1
I think the proof starts from some sort of triangle & using some inequality conditions
 2 years ago

furan143 Group TitleBest ResponseYou've already chosen the best response.1
buddy L'hospital rule is not the actual prrof
 2 years ago

furan143 Group TitleBest ResponseYou've already chosen the best response.1
srry proof
 2 years ago

ankit709 Group TitleBest ResponseYou've already chosen the best response.0
I KNOW but u also know that proof of this equation is 2 long
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
i think for the time being, it is enough that the limit of that is = 1 .... as i will advance in this calculus, i will come across the proof soon and become familiar with that ...
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
really too long ? i thought it would be very simple
 2 years ago

furan143 Group TitleBest ResponseYou've already chosen the best response.1
okay then you better use L'hospital's rule then
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
yah.... i will ... :) thanks all frnds in here .. :) :) :) :) :) :) :) :) :) :) :) :) :) :) :)
 2 years ago

furan143 Group TitleBest ResponseYou've already chosen the best response.1
actually sandwich theorem is like the foundation of calculus
 2 years ago

furan143 Group TitleBest ResponseYou've already chosen the best response.1
proof is not that long but concept is difficult
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
sandwich.... i need to work up at great deal :) :) i will .. bcoz i want to be so perfect in calculus :)
 2 years ago

furan143 Group TitleBest ResponseYou've already chosen the best response.1
I remembers the last step
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
it's alright no problem. thanks you all alot...... really helpful for me.... :)
 2 years ago

CeW Group TitleBest ResponseYou've already chosen the best response.0
sin(x) for small x is x. x/x is 1 for any x.
 2 years ago

furan143 Group TitleBest ResponseYou've already chosen the best response.1
cosx<(sinx/x)<1 here (sinx/x) is sandwiched between cosx & 1 (here not that cosx is also 1 when x tends to zero so sinx/x has no other option other than to tend to zero) that's why it has got the name sandwich or squeeze theorem
 2 years ago

CeW Group TitleBest ResponseYou've already chosen the best response.0
sin(x) / x does not approach 0 in the limit of x > 0 !!
 2 years ago

furan143 Group TitleBest ResponseYou've already chosen the best response.1
you are right cew
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
santosh r u there?
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
hi experimentX, how are you brooo...
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
doing fine ... i might be offline pretty soon .. dw:1334192708048:dw
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
before being, could you expect to have some time with me or not ?
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
open these three :)
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
you see arc there = it's value = \(r\theta\), when \( \theta>0\), the ARC and H seem to be one line. or h/rQ > tends to one as Q>0 h/r = sinQ => sinQ/Q>1 as Q>0
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
i want to know why epsilon is smaller than a  x0 and x1  a
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
yah.... both approach toward 0 i saw that
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
It's not both approach to zero ... it's how their ratio approach as Q approaches to zero > that is limit.
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
why epsilon is smaller than a  x0 and x1  a ............................... :)
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
how is epsilon defined??
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
i know how epsilon is defined but why epsilon is smaller than a  x0 and x1  a ............................... :)
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
i don't know how epsilon is defined ... is it xa < epsilon or f(x)  L  < epsilon
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
omggggggggggggg... how i can get answer to my question... here no one knows about limit definition properly..... ... leave it i try to google it... :D
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
thanks experimentX..... :) :)
 2 years ago

jatinbansalhot Group TitleBest ResponseYou've already chosen the best response.0
ExperimentX... I go and study mathematics more and more if again any ques i would come back :) take care brooo :)
 2 years ago

experimentX Group TitleBest ResponseYou've already chosen the best response.0
sure ...
 2 years ago
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