Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
find out the limit of the following
( sin x ) / x where x > 0
 2 years ago
 2 years ago
find out the limit of the following ( sin x ) / x where x > 0
 2 years ago
 2 years ago

This Question is Closed

jatinbansalhotBest ResponseYou've already chosen the best response.0
plz explain too . i found out it to be 0. u r right it is 1 how
 2 years ago

furan143Best ResponseYou've already chosen the best response.1
answer is 1,actually it's proof is a bit theoretical .if you want any proof please refer some standard text
 2 years ago

furan143Best ResponseYou've already chosen the best response.1
it's proof is well known and is known as sandwich theorem
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
as x reduces, the sin of x also reduces, then why 1
 2 years ago

ankit709Best ResponseYou've already chosen the best response.0
if u put the value of limit then u will get 0/0 form
 2 years ago

furan143Best ResponseYou've already chosen the best response.1
actually 0/0 is a indeterminate value
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
derivative ? but i don't know the derivative i'm beginner but soon be older :D :D hahahaa
 2 years ago

ankit709Best ResponseYou've already chosen the best response.0
this is L hospital rule
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
furan.. yah that would be indeterminate state
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
ohhh.. hospital ....
 2 years ago

furan143Best ResponseYou've already chosen the best response.1
I think the proof starts from some sort of triangle & using some inequality conditions
 2 years ago

furan143Best ResponseYou've already chosen the best response.1
buddy L'hospital rule is not the actual prrof
 2 years ago

ankit709Best ResponseYou've already chosen the best response.0
I KNOW but u also know that proof of this equation is 2 long
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
i think for the time being, it is enough that the limit of that is = 1 .... as i will advance in this calculus, i will come across the proof soon and become familiar with that ...
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
really too long ? i thought it would be very simple
 2 years ago

furan143Best ResponseYou've already chosen the best response.1
okay then you better use L'hospital's rule then
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
yah.... i will ... :) thanks all frnds in here .. :) :) :) :) :) :) :) :) :) :) :) :) :) :) :)
 2 years ago

furan143Best ResponseYou've already chosen the best response.1
actually sandwich theorem is like the foundation of calculus
 2 years ago

furan143Best ResponseYou've already chosen the best response.1
proof is not that long but concept is difficult
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
sandwich.... i need to work up at great deal :) :) i will .. bcoz i want to be so perfect in calculus :)
 2 years ago

furan143Best ResponseYou've already chosen the best response.1
I remembers the last step
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
it's alright no problem. thanks you all alot...... really helpful for me.... :)
 2 years ago

CeWBest ResponseYou've already chosen the best response.0
sin(x) for small x is x. x/x is 1 for any x.
 2 years ago

furan143Best ResponseYou've already chosen the best response.1
cosx<(sinx/x)<1 here (sinx/x) is sandwiched between cosx & 1 (here not that cosx is also 1 when x tends to zero so sinx/x has no other option other than to tend to zero) that's why it has got the name sandwich or squeeze theorem
 2 years ago

CeWBest ResponseYou've already chosen the best response.0
sin(x) / x does not approach 0 in the limit of x > 0 !!
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
santosh r u there?
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
hi experimentX, how are you brooo...
 2 years ago

experimentXBest ResponseYou've already chosen the best response.0
doing fine ... i might be offline pretty soon .. dw:1334192708048:dw
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
before being, could you expect to have some time with me or not ?
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
open these three :)
 2 years ago

experimentXBest ResponseYou've already chosen the best response.0
you see arc there = it's value = \(r\theta\), when \( \theta>0\), the ARC and H seem to be one line. or h/rQ > tends to one as Q>0 h/r = sinQ => sinQ/Q>1 as Q>0
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
i want to know why epsilon is smaller than a  x0 and x1  a
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
yah.... both approach toward 0 i saw that
 2 years ago

experimentXBest ResponseYou've already chosen the best response.0
It's not both approach to zero ... it's how their ratio approach as Q approaches to zero > that is limit.
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
why epsilon is smaller than a  x0 and x1  a ............................... :)
 2 years ago

experimentXBest ResponseYou've already chosen the best response.0
how is epsilon defined??
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
i know how epsilon is defined but why epsilon is smaller than a  x0 and x1  a ............................... :)
 2 years ago

experimentXBest ResponseYou've already chosen the best response.0
i don't know how epsilon is defined ... is it xa < epsilon or f(x)  L  < epsilon
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
omggggggggggggg... how i can get answer to my question... here no one knows about limit definition properly..... ... leave it i try to google it... :D
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
thanks experimentX..... :) :)
 2 years ago

jatinbansalhotBest ResponseYou've already chosen the best response.0
ExperimentX... I go and study mathematics more and more if again any ques i would come back :) take care brooo :)
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.