If there is a mutation in a zygote, where is it likely to be found in the fetus? Answer The mutation will occur in all the cells of the fetus since they all formed by mitosis from the zygote. The mutation will only be found in the types of cells in the fetus that could be harmed by the mutation and not in any others. The mutation will only be in the one cell that was the original zygote and the other cells of the fetus will not have it. The mutation will show up in any fetal cells formed by mitosis but not in those formed by meiosis.

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If there is a mutation in a zygote, where is it likely to be found in the fetus? Answer The mutation will occur in all the cells of the fetus since they all formed by mitosis from the zygote. The mutation will only be found in the types of cells in the fetus that could be harmed by the mutation and not in any others. The mutation will only be in the one cell that was the original zygote and the other cells of the fetus will not have it. The mutation will show up in any fetal cells formed by mitosis but not in those formed by meiosis.

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If it is a human zygote with no mutations, then it will contain 46 chromosomes. Each parent gives the zygote 23 chromosomes. All human gametes without mutations contain 23 and when joined during fertilization they form a zygote with 46 chromosomes. However, chromosome number varies by species, for example a normal pigeon zygote would have 80 chromosomes. All zygotes have their adult number of chromosomes, once again assuming there are not mutations. See the related links for a list of the adult and thus the zygote number of chromosomes.
Not done... just give me a second (;
Equilibrium is defined as the state at which the fraction of the population having harmful mutations is constant. This state should eventually be reached if conditions are more or less unchanging. The first result we need to know is simple and very surprising -- when a population is at equilibrium, then the chance that a gamete (egg or sperm) will have a new, harmful mutation not possessed by the parents as gametes is smaller than the chance that a zygote (fertilized egg) will die without offspring. It doesn't matter whether the mutation is dominant or recessive or how harmful the mutation is, since less harmful mutations will spread to more of the population. It's not necessarily the zygotes that have the harmful mutations that are unable to reproduce, but the rate of harmful mutation still influences the chances of not reproducing as stated above. Put another way, the chance that a zygote can survive and have offspring is less than the chance that a gamete has no new harmful mutations, when the population is at equilibrium.

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Um...I think its this one: The mutation will occur in all the cells of the fetus since they all formed by mitosis from the zygote. What do u think?
the second choice is the correct. a mutations happens in a specific gene and this particular gene may be expressed in a particular tissue and not other. surely you know that although in an organism all the cells carry the same genetic info. but cells are different because each one expresses certain genes and not others. hope im not confusing.
This is a confusing question and I think evergirl is right that the mutation will be present in all the cells of the foetus. However Phascolarctos is correct in stating that the mutation will only be important in cells where the gene in question is expressed. Depends if you mean genotype (in which case it's each cell) or phenotype (in which case it's only certain cells affected). Hope this clears things up.

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