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If the perimeter of square 2 is 200 units, and the perimeter of square 1 is 150 units, what is the perimeter of square 3?
A. 62.5 units
B. 500 units
C. 125 units
D. 250 units
 2 years ago
 2 years ago
If the perimeter of square 2 is 200 units, and the perimeter of square 1 is 150 units, what is the perimeter of square 3? A. 62.5 units B. 500 units C. 125 units D. 250 units
 2 years ago
 2 years ago

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alainabbyboo22Best ResponseYou've already chosen the best response.1
I am unsure how to do that.
 2 years ago

davidkircosBest ResponseYou've already chosen the best response.1
Find the side lengths of both. Perimeter/4 and then use the pythagorean theorem.
 2 years ago

davidkircosBest ResponseYou've already chosen the best response.1
Which part are you unsure on?
 2 years ago

alainabbyboo22Best ResponseYou've already chosen the best response.1
The whole thing.
 2 years ago

davidkircosBest ResponseYou've already chosen the best response.1
Ok so find the side lengths of the Square 1 and 2 first. Side Length = Perimeter /4 Can you do that?
 2 years ago

davidkircosBest ResponseYou've already chosen the best response.1
Then, (Side Length 1)^2+(Side length 2)^2 = (Side Length 3)^2. And once you solve for Side Length 3 you multiply it by 4 to the perimeter.
 2 years ago

alainabbyboo22Best ResponseYou've already chosen the best response.1
Can this be put into equation form? Like more understandably? I'm just really confused on it right now. :/
 2 years ago

davidkircosBest ResponseYou've already chosen the best response.1
Sure. Square 1 has a perimeter of 150. That means that each side is one fourth of that because all sides are the same length on a square. So 150/4 = 37.5 Do the same thing for Square 2. 200/4 = 50. dw:1334176657772:dw Then you have the triangle: dw:1334176742025:dw And when you solve for the hypotenuse, that is the side length of the third square. \[(37.5)^2+50^2=c^2\] Solving: \[\sqrt{(150/4)^2+50^2}\] Which equals 62.5. Then times that by 4 to get your answer of 250 for the perimeter of square 3.
 2 years ago
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