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Aadarsh Group Title

PQRS is a kite. PQ = 7, QR = 11, QS = 10. M is the mid-pint of PR. Find QM^2.

  • 2 years ago
  • 2 years ago

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  1. Ishaan94 Group Title
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    Can you draw a figure?

    • 2 years ago
  2. Aadarsh Group Title
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    Sure. Please wait.

    • 2 years ago
  3. Aadarsh Group Title
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    |dw:1334216371667:dw|

    • 2 years ago
  4. apoorvk Group Title
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    |dw:1334216398007:dw| M is mid pt of PR or QS??

    • 2 years ago
  5. lgbasallote Group Title
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    if QS = 10 then QM = 5 5^2 is 25 right?

    • 2 years ago
  6. Aadarsh Group Title
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    @lgbasallote , u r wrong.

    • 2 years ago
  7. Aadarsh Group Title
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    M is mid-point of PR.

    • 2 years ago
  8. Aadarsh Group Title
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    I have done the answer, shall I post it? Will u correct it?

    • 2 years ago
  9. lgbasallote Group Title
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    ahhh found it now >:))

    • 2 years ago
  10. thushananth01 Group Title
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    \[\frac{\sqrt{24}+\sqrt{96}}{2}\]

    • 2 years ago
  11. Aadarsh Group Title
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    Wrong again.

    • 2 years ago
  12. thushananth01 Group Title
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    that is equal to PM

    • 2 years ago
  13. apoorvk Group Title
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    Okay let me think good one. lol. Done.|dw:1334216749935:dw| wait let me type

    • 2 years ago
  14. thushananth01 Group Title
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    Cos rule i guess...what is QRM=

    • 2 years ago
  15. thushananth01 Group Title
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    sorry QPM?

    • 2 years ago
  16. Aadarsh Group Title
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    QPM is not given.

    • 2 years ago
  17. lgbasallote Group Title
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    let midpoint of QS = A sqrt (11^2 - 5^2) = AR AR = sqrt (121-25) AR = sqrt (96) AR = 4 sqrt (6) PM + AR = PR + MA PM = PR/2 PR/2 + 4 sqrt 6 = PR + MA lol =)))

    • 2 years ago
  18. thushananth01 Group Title
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    so v can find it using sin x = 5/7

    • 2 years ago
  19. Aadarsh Group Title
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    Shall I say how I did? Please. then u will check and rectify me.

    • 2 years ago
  20. thushananth01 Group Title
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    ok?

    • 2 years ago
  21. apoorvk Group Title
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    yeah aadarsh post i am not in the patient mood to type such long replies right now.

    • 2 years ago
  22. Aadarsh Group Title
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    Just a minute.

    • 2 years ago
  23. thushananth01 Group Title
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    answer is 31 = QM^2= 32

    • 2 years ago
  24. thushananth01 Group Title
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    31*

    • 2 years ago
  25. Aadarsh Group Title
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    How u did @thushananth01 ? Can u say the reason please? U r absolutely right.

    • 2 years ago
  26. thushananth01 Group Title
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    ok first find the full length of PR u can do this first by using pythagoras theorom then u have to add both and divide by 2 to get the midpoint as i gve previous with the radical..that was the length from P to M now we know PM and PQ plus the angle QPM v can find using the sin rule then i got the angle as 45.6 then finally the cose rule\[p^{2}= q^{2} + m^{2} - 2qm (cos P)\] \[7^{2}+7.35^{2} - 2 \times 7 \times 7.35 \cos 45.6 = p^{2}\rightarrow QM^2\]

    • 2 years ago
  27. thushananth01 Group Title
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    \[\frac{\sqrt{24} +\sqrt{96}}{2}\rightarrow PM\]

    • 2 years ago
  28. Aadarsh Group Title
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    Thanks yaar.

    • 2 years ago
  29. thushananth01 Group Title
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    np :)

    • 2 years ago
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