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dpaInc
 2 years ago
Best ResponseYou've already chosen the best response.1(2x3)^(1/2) + x(2x3)^(1/2)

sdavenko
 2 years ago
Best ResponseYou've already chosen the best response.0what about the 2 that is taken from the inside of the function? and thats what i have already but i dont know how to simplify it further

arcticf0x
 2 years ago
Best ResponseYou've already chosen the best response.2That 2 has been cancelled by 1/2 from the exponent. Do you have some answer you have to simplify for?

sdavenko
 2 years ago
Best ResponseYou've already chosen the best response.0oh thanks butthis isnt an integration problem

sdavenko
 2 years ago
Best ResponseYou've already chosen the best response.0the other options are a) 3x3/ sqrt2x3 b.) x/sqrt 2x3 c.) 1/sqrt 2x3 d.)x+3/ sqrt 2x3 e.)5x6/2 sqrt 2x3

arcticf0x
 2 years ago
Best ResponseYou've already chosen the best response.2Simply add the terms, you will get 3x3/(2x3)^(1/2)...Know how?

sdavenko
 2 years ago
Best ResponseYou've already chosen the best response.0no the final step im on is (2x3)^1/2 +(2x)(1/2)(2x3)^1/2

arcticf0x
 2 years ago
Best ResponseYou've already chosen the best response.2Ok, look, we have, (2x3)^(1/2) +x(2x3)^(1/2) => [(2x3)^(1/2) * (2x3)^(1/2) + x ]/(2x3)^(1/2) =>(2x3+x)/(2x3)^(1/2) =>3x3/(2x3)^(1/2)

sdavenko
 2 years ago
Best ResponseYou've already chosen the best response.0ah i feel th feel like i have made this problem harder than it neeeds to be but, why did you multiply (2x3)^(1/2) by (2x3)^(1/2) in the second step?

arcticf0x
 2 years ago
Best ResponseYou've already chosen the best response.2Its the way you add surds, multiply the denominator and join them.

sdavenko
 2 years ago
Best ResponseYou've already chosen the best response.0ok thanks! I really appreciate you're patience

arcticf0x
 2 years ago
Best ResponseYou've already chosen the best response.2I wish i could have done that in proper latex so it'd have been clear before.

sdavenko
 2 years ago
Best ResponseYou've already chosen the best response.0where are you from? what country?
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