## greeneyes<3 Group Title Evaluate w/o using a calulator: sec (11 pi/6) My answer was (2 sqrt3/3) Can someone check if it's right? 2 years ago 2 years ago

1. vi3tbloodxx

sec (11π / 6) is the same as 1 / cos(11π / 6)

2. eigenschmeigen

sec(11pi/6) = 1/cos(11pi/6) cos(11pi/6) we can see from the graph that cos(2pi - x) = cos(x) cos(11pi/6) = cos(2pi - pi/6) = cos(pi/6) = sqrt(3)/2

3. eigenschmeigen

so sec(11pi/6) = 1/(sqrt(3)/2) = 2/sqrt(3) = 2sqrt(3)/3

4. eigenschmeigen

yes you are correct

5. vi3tbloodxx

$1 / \cos(11π / 6) = 1 / \sqrt{3}/2$ $= 2\sqrt{3}/3$

6. greeneyes<3

Thanks smart people lol i thought i had it wrong. :)