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Aadarsh

  • 3 years ago

Area of a regular octagon is 4(root 2 + 1) square units. Find its side.

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  1. Aadarsh
    • 3 years ago
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    |dw:1334302795177:dw|

  2. Aadarsh
    • 3 years ago
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    @Taufique bhai, please help.

  3. Aadarsh
    • 3 years ago
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    Let the side of octagon be "x" units.

  4. fractal5
    • 3 years ago
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    \[4\sqrt{2+1}\] or \[4\sqrt{2}+1\]

  5. Aadarsh
    • 3 years ago
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    |dw:1334303032758:dw| @fractal5 , the first one

  6. fractal5
    • 3 years ago
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    are you sure, because that is = \[4\sqrt{3}\]

  7. Aadarsh
    • 3 years ago
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    Now, |dw:1334303202974:dw|

  8. Aadarsh
    • 3 years ago
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    The actual area is :|dw:1334303237350:dw|

  9. fractal5
    • 3 years ago
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    Area = ( 2 + 2√2 )*(x^2) where x is the side length

  10. Taufique
    • 3 years ago
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    in the regular octagon.there will be 8 equilateral triangle hence let the side is x. then area of octagon=8*area of one equilateral triangle =\[8\times \sqrt{3}\div 4 (x ^{2})\]..find x.

  11. Aadarsh
    • 3 years ago
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    @Taufique bhai, can u say the answer?

  12. fractal5
    • 3 years ago
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    Are you sure they are equilateral? I think in a hexagon they are equil. not octagon

  13. Aadarsh
    • 3 years ago
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    Even I am in doubt whther we will get 8 equilateral traingles or not.

  14. fractal5
    • 3 years ago
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    Just solve the formula I gave

  15. Aadarsh
    • 3 years ago
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    @fractal5 , u r rite. I got it. Can u say how u got it?

  16. Aadarsh
    • 3 years ago
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    @fractal5,can u plz explain the formula how u got it?

  17. Aadarsh
    • 3 years ago
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    @gurvinder bhai, can u explain the formula?

  18. Taufique
    • 3 years ago
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    @Aadarsh fractal is right .. |dw:1334303786166:dw|

  19. Aadarsh
    • 3 years ago
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    Okay. But can u explain the formula which @fractal5 used? plzzzzzzzz

  20. Aadarsh
    • 3 years ago
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    @Taufique bhai, u der?

  21. Taufique
    • 3 years ago
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    |dw:1334304124446:dw| find its area and multiply it by 8 and put it equal to given area in your question...

  22. Aadarsh
    • 3 years ago
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    But, now can u explain the nest step? The height and side in terms of "x"?

  23. Taufique
    • 3 years ago
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    Aadarsh wait.

  24. Aadarsh
    • 3 years ago
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    Okay bhai. I will be coming in 15 minutes after lunch.

  25. Taufique
    • 3 years ago
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    |dw:1334304950665:dw| put the value of tan67.5 deg equal to

  26. Aadarsh
    • 3 years ago
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    Okay bhai. But how to obtain value of tan 67.5?

  27. Taufique
    • 3 years ago
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    tan67.5deg=root2+1 put there and find x

  28. Taufique
    • 3 years ago
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    |dw:1334305364185:dw|

  29. Taufique
    • 3 years ago
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    @Aadarsh ab kho bhai koi problem.. sorry kam kar rha tha college ka project tha.

  30. Taufique
    • 3 years ago
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    Aadarsh khan ho.

  31. Taufique
    • 3 years ago
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    |dw:1334305876442:dw| find tan67.5 from here.

  32. Aadarsh
    • 3 years ago
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    But abhi isko solve kaise karenge?

  33. Taufique
    • 3 years ago
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    tan67.5=x let |dw:1334306229613:dw| x=root2+1 is only possible because 67.5 is in first quadrant and in first quadrant tan ins positive.hence neglect negative value(1-root2)

  34. Aadarsh
    • 3 years ago
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    OH yeah I got it. Thanks bhai!!!!!!!

  35. Taufique
    • 3 years ago
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    ji han vai apko v dhanyabad samajne k liye..

  36. Aadarsh
    • 3 years ago
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    Thanks ji.

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