anonymous
  • anonymous
Area of a regular octagon is 4(root 2 + 1) square units. Find its side.
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1334302795177:dw|
anonymous
  • anonymous
@Taufique bhai, please help.
anonymous
  • anonymous
Let the side of octagon be "x" units.

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anonymous
  • anonymous
\[4\sqrt{2+1}\] or \[4\sqrt{2}+1\]
anonymous
  • anonymous
|dw:1334303032758:dw| @fractal5 , the first one
anonymous
  • anonymous
are you sure, because that is = \[4\sqrt{3}\]
anonymous
  • anonymous
Now, |dw:1334303202974:dw|
anonymous
  • anonymous
The actual area is :|dw:1334303237350:dw|
anonymous
  • anonymous
Area = ( 2 + 2√2 )*(x^2) where x is the side length
anonymous
  • anonymous
in the regular octagon.there will be 8 equilateral triangle hence let the side is x. then area of octagon=8*area of one equilateral triangle =\[8\times \sqrt{3}\div 4 (x ^{2})\]..find x.
anonymous
  • anonymous
@Taufique bhai, can u say the answer?
anonymous
  • anonymous
Are you sure they are equilateral? I think in a hexagon they are equil. not octagon
anonymous
  • anonymous
Even I am in doubt whther we will get 8 equilateral traingles or not.
anonymous
  • anonymous
Just solve the formula I gave
anonymous
  • anonymous
@fractal5 , u r rite. I got it. Can u say how u got it?
anonymous
  • anonymous
@fractal5,can u plz explain the formula how u got it?
anonymous
  • anonymous
@gurvinder bhai, can u explain the formula?
anonymous
  • anonymous
@Aadarsh fractal is right .. |dw:1334303786166:dw|
anonymous
  • anonymous
Okay. But can u explain the formula which @fractal5 used? plzzzzzzzz
anonymous
  • anonymous
@Taufique bhai, u der?
anonymous
  • anonymous
|dw:1334304124446:dw| find its area and multiply it by 8 and put it equal to given area in your question...
anonymous
  • anonymous
But, now can u explain the nest step? The height and side in terms of "x"?
anonymous
  • anonymous
Aadarsh wait.
anonymous
  • anonymous
Okay bhai. I will be coming in 15 minutes after lunch.
anonymous
  • anonymous
|dw:1334304950665:dw| put the value of tan67.5 deg equal to
anonymous
  • anonymous
Okay bhai. But how to obtain value of tan 67.5?
anonymous
  • anonymous
tan67.5deg=root2+1 put there and find x
anonymous
  • anonymous
|dw:1334305364185:dw|
anonymous
  • anonymous
@Aadarsh ab kho bhai koi problem.. sorry kam kar rha tha college ka project tha.
anonymous
  • anonymous
Aadarsh khan ho.
anonymous
  • anonymous
|dw:1334305876442:dw| find tan67.5 from here.
anonymous
  • anonymous
But abhi isko solve kaise karenge?
anonymous
  • anonymous
tan67.5=x let |dw:1334306229613:dw| x=root2+1 is only possible because 67.5 is in first quadrant and in first quadrant tan ins positive.hence neglect negative value(1-root2)
anonymous
  • anonymous
OH yeah I got it. Thanks bhai!!!!!!!
anonymous
  • anonymous
ji han vai apko v dhanyabad samajne k liye..
anonymous
  • anonymous
Thanks ji.

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