Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

acrossBest ResponseYou've already chosen the best response.2
\[f(x)=5\sqrt{\ln x}\]\[g(x)=\sqrt{x}\]\[h(x)=\ln x\]\[f(x)=g(h(x))\]\[g'(x)=\frac{1}{2\sqrt{x}}\]\[h'(x)=\frac{1}{x}\]\[f'(x)=g'(h(x))h'(x)=\frac{1}{2x\sqrt{\ln x}}\]
 2 years ago

acrossBest ResponseYou've already chosen the best response.2
I left out the \(5\), but you know what I mean.
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.0
but what if they mean\[\large \sqrt[5]{\ln x}\]?
 2 years ago

calyneBest ResponseYou've already chosen the best response.0
oh no yeah it's 5th root
 2 years ago

acrossBest ResponseYou've already chosen the best response.2
Then all he has to do is change \(g\) and \(g'\) a little.
 2 years ago

TuringTestBest ResponseYou've already chosen the best response.0
oh good, I got scared for a minute :)
 2 years ago

calyneBest ResponseYou've already chosen the best response.0
and don't use substitution for the composite functions just go at it
 2 years ago

Will!Best ResponseYou've already chosen the best response.1
\[f(x) = (\lnx)^{1 \over 5}\]\[\ln x = u \rightarrow f(x) = u^{1 \over 5}\]\[{df \over du} = {1 \over 5}u^{4 \over 5} \]\[{du \over dx} = {1 \over x}\] \[{df \over dx} = {df \over du}{du \over dx} = {1 \over x} {{1 \over 5}(\ln x)^{4/5}} = {1 \over 5x(lnx)^{4 \over 5}} \]
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.