calyne
Differentiate the function f(x) = sin x ln(5x)



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anonymous
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poduct plus chain rule

anonymous
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\[(fg)'=f'g+g'f\] use
\[f(x)=\sin9x), f'(x)=\cos(x), g(x)=\ln(5x), g'(x)=\frac{1}{x}\]

siddhantsharan
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cosxln5x + sinx/x

anonymous
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typo there
\[f(x)=\sin(x)\]

calyne
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the function is f(x) = sin(x) * ln(5x)

calyne
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the derivative of ln(5x) is 5/x or 1/5x?

siddhantsharan
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None.
Use chain rule
= (1/5x)*5= 1/x