## calyne 3 years ago Differentiate the function g(x) = ln [x*sqrt(x^2 - 1)]

1. myko

$g(x) = \ln (x \sqrt(x^2 - 1))$ this one?

2. myko

use chain rule

3. satellite73

start with $\ln(x)+\frac{1}{2}\ln(x+1)+\frac{1}{2}\ln(x-1)$ and it will be easier

4. calyne

sooo g'(x) = 1/x + 1/x(x+1) + 1/x(x-1) ?

5. calyne

stupid i know but i'm having trouble simplifying that what do i do

6. vi3tbloodxx

g'(x) = 1/x + 1/2(1/(x+1)) + 1/2(1/(x-1)) = 1/x + 1/2(x+1) + 1/2(x-1)

7. calyne

well yeah i got that sorry i typed it wrong but i need to simplify that

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