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calyne

Differentiate the function g(x) = ln [x*sqrt(x^2 - 1)]

  • 2 years ago
  • 2 years ago

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  1. myko
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    \[g(x) = \ln (x \sqrt(x^2 - 1))\] this one?

    • 2 years ago
  2. myko
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    use chain rule

    • 2 years ago
  3. satellite73
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    start with \[\ln(x)+\frac{1}{2}\ln(x+1)+\frac{1}{2}\ln(x-1)\] and it will be easier

    • 2 years ago
  4. calyne
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    sooo g'(x) = 1/x + 1/x(x+1) + 1/x(x-1) ?

    • 2 years ago
  5. calyne
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    stupid i know but i'm having trouble simplifying that what do i do

    • 2 years ago
  6. vi3tbloodxx
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    g'(x) = 1/x + 1/2(1/(x+1)) + 1/2(1/(x-1)) = 1/x + 1/2(x+1) + 1/2(x-1)

    • 2 years ago
  7. calyne
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    well yeah i got that sorry i typed it wrong but i need to simplify that

    • 2 years ago
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