A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
It takes Tom 15 minutes to wash a car.It takes only 10 minutes with jerry helping.how long should it take jerry to wash the car by himself?
A. 6 minutes
b. 12.5 minutes
c. none of these choices are correct.
d. 25 minutes
e. 5 minutes
anonymous
 4 years ago
It takes Tom 15 minutes to wash a car.It takes only 10 minutes with jerry helping.how long should it take jerry to wash the car by himself? A. 6 minutes b. 12.5 minutes c. none of these choices are correct. d. 25 minutes e. 5 minutes

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0would take 30 minutes

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Tom can wash 1/15 of the car in 1 minute Together they wash 1/10 of the car in 1 minutes. The part Tom does + the part Jerry does = the part they do together. So \[\frac{1}{15}+\frac{1}{x}=\frac{1}{10}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can you solve that iheart?

Mertsj
 4 years ago
Best ResponseYou've already chosen the best response.0Multiply each term by the common denominator which is 30x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok  first find LCM of 10,15 and x this is 30x multiply each term by 30x gives 30x 30x 30x  +  =  15 x 10 dividing each term 2x + 30 = 3x 30 = 3x  2x = x so x = 30 none of the choices are correct  as kumar said the answer is c
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.