Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

sonofa_nh

  • 4 years ago

A 1.50-µF capacitor charged to 40.0 V and a 2.40-µF capacitor charged to 15.0 V are connected to each other, with the positive plate of each connected to the negative plate of the other. What is the final charge on the 1.50-µF capacitor

  • This Question is Closed
  1. cookies
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    experiment dude u multitask like crazy

  2. experimentX
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1334363905084:dw|

  3. experimentX
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and we have formula, Q = CV I suppose. Let's calculate the charges on both.

  4. experimentX
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    still there??

  5. sonofa_nh
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yea i got 5 minutes to submit it...time to throw up an airball and hope for the best lol

  6. experimentX
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    well, Calculate charges on both ,,, subtract the charges. and distribute the charges between them proportional to their capacitance.

  7. sonofa_nh
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    thx for your help

  8. sonofa_nh
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    :)

  9. experimentX
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you are welcome.

  10. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy