A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1you know what you did to x in calc 1 and 2? now do it to y and z

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.2im good with matrices and all that. it's when it comes a part of vectors that i'm not understanding really well

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1334382554391:dw

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1vector just point in a direction

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1good, casue i aint none to goog at mindreading :)

ald0024
 2 years ago
Best ResponseYou've already chosen the best response.0I'm in the same position! Some teacher failed me along the way in the vector department!

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.2given vectors a=2xi+2xj+xk, b=xi2xj+2xk and c=2xixj2xk show that {a,b,c} is a negative orthogonal base for x<0

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1an orthogonal base is such that each vector is orthogonal to each other

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1since x is a common factor of everyting; we can ignore it

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.2for wich value(s) of x, will {a,b,c} be an orthornomal base?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1a.b =2xi+2xj+xk, xi2xj+2xk  2  4 + 2 = 0 b.c=2xixj 2xk xi2xj+2xk  2 + 2  4 = 0 a.c =2xi+2xj+xk, xi2xj+2xk  2  4 + 2 = 0 so it is orthonormal

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.2i did that, but when it comes to the second part i get lost.

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1and since x is just a common "scalar" id assume x can be anything; but maybe zero since people hate zeros

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1" Moreover, they are all required to have length one" http://mathworld.wolfram.com/OrthonormalBasis.html

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.2\[a=\sqrt{4x^2+4x^2+x^2}=\sqrt{9x^2}=3x\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1looks like x needs to be the 1/... yeah, that

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.2so i did it for all 3 vectors and they all were 3x

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1x is the scalar that makes them go unit i believe; which means the x = 1 over magnitude

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.2so since a=b=c=3x=1 > x=1/3

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1x is not part of the length; its factored out and eqauted to the reciprocal of the magnitude

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1each vector has the same basic components so they are going to have the same lengths <2,2,1> ; sqrt(4+4+1) = sqrt(9) = 3 x = 1/3 yep

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.2there's a third part :X

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1and the negative is just 1/3 right?

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.2Find the coordinates to v in the orthornomal base obtained, in wich v in the canonical base has coordinates (1,2,3)

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1now your just making up words :P

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.2im sorry, its in portuguese, i'm translating :P

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1standard basis perhaps?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1row reduce your vector basis next to this new vector from the standard bases

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1how should we define our vectors in the basis? what should our x y and z parts correlate to?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1it matters; switching columns of a matrix alters things; switching rows doent

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.2for the first vector and i did the same to the other 2

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1v1=2,2,1 v2=1,2,2 v3=2,1,2 \[\frac{1}{3}\begin{vmatrix}v_1&v_2&v_3\\2&1&2\\2&2&1\\1&2&2\end{vmatrix}\ \begin{vmatrix}c_1\\c_2\\c_3\end{vmatrix}=\begin{vmatrix}1\\2\\3\end{vmatrix}\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1your vectors need to be put in columns, not rows

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1multiply both sides by 3 to get rid of the scalar

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1\[RREF\begin{vmatrix}2&1&2&&3\\2&2&1&&6\\1&2&2&&9\end{vmatrix}\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1the left goes to identity and the right goes to the coord vector in the basis

nickymarden
 2 years ago
Best ResponseYou've already chosen the best response.2guess im not as bad as i thought? at least i got the first 2 parts correct :p and thanks for explaining the rest :))

Rogue
 2 years ago
Best ResponseYou've already chosen the best response.0I'd like to learn multivariate as well to get a head start on next year, but I'm not a fan of matrices and vectors :(
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.