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anonymous
 4 years ago
Can anyone help me?
anonymous
 4 years ago
Can anyone help me?

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dcolley
 4 years ago
Best ResponseYou've already chosen the best response.0we just started learning this

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm having troubles with it. I know b<0, but not a

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh ,, I posted the wrong question

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Though, the previous one is also the question I don't know. Just do it later.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if x was zero then b would be........

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I told you I know b<0. I don't know range of value for a only

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0we know b is negative ... x is postive /...... x^2 is postive ......x^2 is negative... so we have two negative terms but still ax is reaching above the x axis... we x is postive ..... so a must be postive to make ax postive plus ax has to be greater than x^2+b

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0OMG, I've never though in that way. Thank you!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cool but b could be so large like 1000000 that it would never go above the line
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