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RolyPoly

  • 4 years ago

Can anyone help me?

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  1. dcolley
    • 4 years ago
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    with what?

  2. RolyPoly
    • 4 years ago
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    That one

  3. dcolley
    • 4 years ago
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    we just started learning this

  4. RolyPoly
    • 4 years ago
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    I'm having troubles with it. I know b<0, but not a

  5. RolyPoly
    • 4 years ago
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    Oh ,, I posted the wrong question

  6. RolyPoly
    • 4 years ago
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    There you are~

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  7. RolyPoly
    • 4 years ago
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    Though, the previous one is also the question I don't know. Just do it later.

  8. benice
    • 4 years ago
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    if x was zero then b would be........

  9. RolyPoly
    • 4 years ago
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    I told you I know b<0. I don't know range of value for a only

  10. benice
    • 4 years ago
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    a has to be postive

  11. RolyPoly
    • 4 years ago
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    why?

  12. benice
    • 4 years ago
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    we know b is negative ... x is postive /...... x^2 is postive ......-x^2 is negative... so we have two negative terms but still ax is reaching above the x axis... we x is postive ..... so a must be postive to make ax postive plus ax has to be greater than -x^2+b

  13. RolyPoly
    • 4 years ago
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    OMG, I've never though in that way. Thank you!

  14. benice
    • 4 years ago
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    cool but b could be so large like -1000000 that it would never go above the line

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