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dcolleyBest ResponseYou've already chosen the best response.0
we just started learning this
 2 years ago

RolyPolyBest ResponseYou've already chosen the best response.0
I'm having troubles with it. I know b<0, but not a
 2 years ago

RolyPolyBest ResponseYou've already chosen the best response.0
Oh ,, I posted the wrong question
 2 years ago

RolyPolyBest ResponseYou've already chosen the best response.0
Though, the previous one is also the question I don't know. Just do it later.
 2 years ago

beniceBest ResponseYou've already chosen the best response.1
if x was zero then b would be........
 2 years ago

RolyPolyBest ResponseYou've already chosen the best response.0
I told you I know b<0. I don't know range of value for a only
 2 years ago

beniceBest ResponseYou've already chosen the best response.1
we know b is negative ... x is postive /...... x^2 is postive ......x^2 is negative... so we have two negative terms but still ax is reaching above the x axis... we x is postive ..... so a must be postive to make ax postive plus ax has to be greater than x^2+b
 2 years ago

RolyPolyBest ResponseYou've already chosen the best response.0
OMG, I've never though in that way. Thank you!
 2 years ago

beniceBest ResponseYou've already chosen the best response.1
cool but b could be so large like 1000000 that it would never go above the line
 2 years ago
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