Phone calls arrive at the rate of 15 per hour at the reservation desk for a hotel, according to a poisson distribution. If no calls are currently being processed, and the desk employee leaves the desk for a 10-minute break, what is the probability the phone will ring while he is gone on his break?

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Phone calls arrive at the rate of 15 per hour at the reservation desk for a hotel, according to a poisson distribution. If no calls are currently being processed, and the desk employee leaves the desk for a 10-minute break, what is the probability the phone will ring while he is gone on his break?

Mathematics
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if no calls are being processed is just to throw you off as s poisson distribution is a memoryless property you want to find the prob of zero rings and then take that away from one http://www.youtube.com/watch?v=Fk02TW6reiA this video should explain it
i watched that video just now but it did not help at all. Could you write down the solution for me?
so we are dealing with a 10min time frame .... find the expected value 1/6*15=2.5|dw:1334385857866:dw|

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why is it 6*15?
10 minutes is 1/6 of an hour .. you are gettin the expected value for that time frame and calling it alpha
x=0 as this as said earlier is no call... and we want 1 minus that prob above
oh now i understand. Thank you so much. I am suck at poisson distribution problems and it seems like problems are having different patterns.
i suck at them too... watch that video again, it helps me
okay. I will try. Do you have skype or messenger? I feel like contacting you for math problems.
if I'm here ill gladly help.
okay.
Help me with this another problem. Celina is an executive who receives an average of 8 phone calls each afternoon between 2 and 4. Assuming that the calls are Poisson distributed, what is the probability that celina will receive three or more calls between 2:30 and 3:30?
so the average is 4 an hour..... the time frame your dealing with is an hour..... ie2.30-3.30.....
so alpha is =4 now P(x>=3)=P(x=3)+P(x=4)+(x=5)...... .alll the way to infinity but life is short so we calculate 1-{P(x=0)+P(x=1)+P(x=2)}
Thank you.

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