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anonymous
 4 years ago
Differentiate the function g(x) = ln[x(sqrt(x^2  1))]
anonymous
 4 years ago
Differentiate the function g(x) = ln[x(sqrt(x^2  1))]

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and SIMPLIFY THE ANSWER

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i got up to g'(x) = 1/x + 1/[2(x+1)] + 1/[2(x1)] i can't simplify it i'm retarded help me

ash2326
 4 years ago
Best ResponseYou've already chosen the best response.2We have \[ g(x)= \ln( x \sqrt { x^21})\] \[g'(x)= \frac{1}{ x\sqrt {x^21} } \times ( \sqrt { x^21} + x \times \frac{2x}{2 \sqrt {x^21}}) \] or \[g'(x)= \frac{1}{ x\sqrt {x^21} } \times ( \sqrt { x^21} + x \times \frac{x}{ \sqrt {x^21}}) \] simplifying now \[g'(x)= \frac{1}{ x\sqrt {x^21} } \times ( \frac{x^21+x^2}{ \sqrt {x^21}}) \] \[g'(x)= \frac{2x^21}{ x( x^21)} \]
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