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Sarkar Group TitleBest ResponseYou've already chosen the best response.0
use quotient rule...
 2 years ago

bmp Group TitleBest ResponseYou've already chosen the best response.0
1/(x(lnx+1)^2) by using the quotient rule :)
 2 years ago

calyne Group TitleBest ResponseYou've already chosen the best response.0
i'm trying it i'm not sure if i'm getting it just show me so i can check
 2 years ago

Sarkar Group TitleBest ResponseYou've already chosen the best response.0
dw:1334417837384:dw
 2 years ago

calyne Group TitleBest ResponseYou've already chosen the best response.0
like that helps
 2 years ago

bmp Group TitleBest ResponseYou've already chosen the best response.0
It's (1+ln2)/(x(ln2x + 1)^2)
 2 years ago

calyne Group TitleBest ResponseYou've already chosen the best response.0
how did you get that
 2 years ago

Sarkar Group TitleBest ResponseYou've already chosen the best response.0
dw:1334418069246:dw
 2 years ago

calyne Group TitleBest ResponseYou've already chosen the best response.0
so then [(1+ln(x)) / x] / [(1+ln(2x))^2] is what
 2 years ago

calyne Group TitleBest ResponseYou've already chosen the best response.0
i mean (1+ln(2)) / x
 2 years ago

bmp Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=d%28lnx%2F%281%2Bln2x%29%29%2Fdx Take a look at show steps :)
 2 years ago

Sarkar Group TitleBest ResponseYou've already chosen the best response.0
([(1+ln(2x)) / x][(lnx)/x] )/ [(1+ln(2x))^2]
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
super secret tip: the quotient rule is best avoided. better to rewrite the problem and use the product rule
 2 years ago

Sarkar Group TitleBest ResponseYou've already chosen the best response.0
but that involves confusion using the power of 1 ,i feel...
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
yes, so if you know the chain rule this shouldn't be too hard\[\ln x(1+\ln(2x))^{1}\]
 2 years ago

Sarkar Group TitleBest ResponseYou've already chosen the best response.0
thanks for informin@Turingtest.
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.0
so @calyne try this with product rule\[\ln x(1+\ln(2x))^{1}\]let\[u=\ln x\]\[v=(1+\ln(2x))^{1}\]
 2 years ago

calyne Group TitleBest ResponseYou've already chosen the best response.0
oh nvm nvm sry oh god
 2 years ago
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