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calyne
 3 years ago
Differentiate the function f(x) = (lnx)/(1+ln(2x))
calyne
 3 years ago
Differentiate the function f(x) = (lnx)/(1+ln(2x))

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bmp
 3 years ago
Best ResponseYou've already chosen the best response.01/(x(lnx+1)^2) by using the quotient rule :)

calyne
 3 years ago
Best ResponseYou've already chosen the best response.0i'm trying it i'm not sure if i'm getting it just show me so i can check

bmp
 3 years ago
Best ResponseYou've already chosen the best response.0It's (1+ln2)/(x(ln2x + 1)^2)

calyne
 3 years ago
Best ResponseYou've already chosen the best response.0so then [(1+ln(x)) / x] / [(1+ln(2x))^2] is what

bmp
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=d%28lnx%2F%281%2Bln2x%29%29%2Fdx Take a look at show steps :)

Sarkar
 3 years ago
Best ResponseYou've already chosen the best response.0([(1+ln(2x)) / x][(lnx)/x] )/ [(1+ln(2x))^2]

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0super secret tip: the quotient rule is best avoided. better to rewrite the problem and use the product rule

Sarkar
 3 years ago
Best ResponseYou've already chosen the best response.0but that involves confusion using the power of 1 ,i feel...

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0yes, so if you know the chain rule this shouldn't be too hard\[\ln x(1+\ln(2x))^{1}\]

Sarkar
 3 years ago
Best ResponseYou've already chosen the best response.0thanks for informin@Turingtest.

TuringTest
 3 years ago
Best ResponseYou've already chosen the best response.0so @calyne try this with product rule\[\ln x(1+\ln(2x))^{1}\]let\[u=\ln x\]\[v=(1+\ln(2x))^{1}\]
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