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Differentiate the function f(x) = (lnx)/(1+ln(2x))

Mathematics
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use quotient rule...
1/(x(lnx+1)^2) by using the quotient rule :-)
Oops, sorry

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Other answers:

i'm trying it i'm not sure if i'm getting it just show me so i can check
|dw:1334417837384:dw|
like that helps
It's (1+ln2)/(x(ln2x + 1)^2)
how did you get that
|dw:1334418069246:dw|
so then [(1+ln(x)) / x] / [(1+ln(2x))^2] is what
i mean (1+ln(2)) / x
http://www.wolframalpha.com/input/?i=d%28lnx%2F%281%2Bln2x%29%29%2Fdx Take a look at show steps :-)
([(1+ln(2x)) / x]-[(lnx)/x] )/ [(1+ln(2x))^2]
super secret tip: the quotient rule is best avoided. better to rewrite the problem and use the product rule
but that involves confusion using the power of -1 ,i feel...
yes, so if you know the chain rule this shouldn't be too hard\[\ln x(1+\ln(2x))^{-1}\]
thanks for informin@Turingtest.
so @calyne try this with product rule\[\ln x(1+\ln(2x))^{-1}\]let\[u=\ln x\]\[v=(1+\ln(2x))^{-1}\]
oh nvm nvm sry oh god

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