calyne
Differentiate the function f(x) = (lnx)/(1+ln(2x))



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Sarkar
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use quotient rule...

bmp
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1/(x(lnx+1)^2) by using the quotient rule :)

bmp
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Oops, sorry

calyne
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i'm trying it i'm not sure if i'm getting it just show me so i can check

Sarkar
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dw:1334417837384:dw

calyne
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like that helps

bmp
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It's
(1+ln2)/(x(ln2x + 1)^2)

calyne
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how did you get that

Sarkar
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dw:1334418069246:dw

calyne
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so then [(1+ln(x)) / x] / [(1+ln(2x))^2] is what

calyne
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i mean (1+ln(2)) / x


Sarkar
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([(1+ln(2x)) / x][(lnx)/x] )/ [(1+ln(2x))^2]

TuringTest
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super secret tip: the quotient rule is best avoided. better to rewrite the problem and use the product rule

Sarkar
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but that involves confusion using the power of 1 ,i feel...

TuringTest
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yes, so if you know the chain rule this shouldn't be too hard\[\ln x(1+\ln(2x))^{1}\]

Sarkar
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thanks for informin@Turingtest.

TuringTest
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so @calyne try this with product rule\[\ln x(1+\ln(2x))^{1}\]let\[u=\ln x\]\[v=(1+\ln(2x))^{1}\]

calyne
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oh nvm nvm sry oh god