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AAD-wait for me...

Solve:
[1/(sin 45 sin 46)] + [1/(sin 47 sin 48)] + ........................+ [1(sin 133 sin 134)]

good one...

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FNSTSE Question

i think mani's approach is good!!!!

|dw:1334419200461:dw|

So, we get |dw:1334419282831:dw| ?

Use (sinx)^2=1-cos2x/2
sinxcosx=sin2x/2
Where did sin1 and cos1 go, sarkar?

sin 90 =1, isn't it?

Actually, sin1=1.17. Yes, aadarsh. You sure you got that general term, Aadarsh?

sin1 almost equals 1

Uh oh, I am not getting a simplified general term using that. Let me think on this.

Sure. Try to post it as soon as possible.

note=everyone who have answered this Q is of level 30 and above....lol

I think most of them have left this question. i asked to my teacher, she couldn't answer it.

Great!!!!!! Thanks @Recursing . But I want to know the procedure.

Oh, wait, i used radians.

So, final answer = ? I could n't understand clearly.

The first one

Oh hmm

\[\large \sum_{k=0}^{44} \frac1{\sin(45+2k)\cdot\sin(45+2k+1)}\]

How tro solve it? What is the final answer?

\[\large \sum_{k=0}^{44} \frac{2}{\sin(4k+1) + \cos 1}\]

This must be a Multiple Choice Question, what are the options?

Subjective Question, 3 marks

Welcome bhaijan............

hehe Bhaijan...

heheheheheheh

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