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calyne
 3 years ago
Differentiate the function y = ln 2x5x^2
calyne
 3 years ago
Differentiate the function y = ln 2x5x^2

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amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0\[[ln(u)]'=\frac{u'}{u}\]

calyne
 3 years ago
Best ResponseYou've already chosen the best response.1what are those brackets or 

calyne
 3 years ago
Best ResponseYou've already chosen the best response.1because it's not lnu it's lnu

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0those are just for grouping; it means that the whole of it is derived and not just the (u) part

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0i believe it goes piece wise in the end

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0or you can use the sqrt(u)^2 trick

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{dx}ln(\sqrt{u\ }^2)=\frac{(\sqrt{u\ }^2)'}{ \sqrt{u\ }^2}\to\ \frac{2\sqrt{u\ }*\sqrt{u}'}{ \sqrt{u\ }^2}\]

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0if i follow that derivatives i think it would look like this ... but best to check with the wolf

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=derivative+ln+%7C2x5x%5E2%7C the wolf doesnt seem to go thru the hoopla tho

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{2\sqrt{u\ }}{ \sqrt{u\ }^2}\sqrt{u}'\] \[\frac{2\sqrt{u\ }}{ \sqrt{u\ }^2}\frac{u'}{2\sqrt{u}}=\frac{u'}{ \sqrt{u\ }^2}\to\ \frac{u'}{ u}\]

calyne
 3 years ago
Best ResponseYou've already chosen the best response.1whatevr it's 1/(2x5x^2) * (10x+1) = 10x+1 / 5x^2+x2 woohoo
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