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Differentiate the function y = ln(e^[-x] + xe^[-x])

Mathematics
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apply chain rule
hello
who? me?

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Other answers:

.....
help me
u know how to apply chain rule? @calyne?
yeah i know that pellet what's the derivative of e^[-x]
wait a while..
what
are you joking
1 Attachment
that will be dy/dx, in the picture^^
THAT WAS FAST!!! kudos @arnab09
y'=-x\(x+1),here is the steps :Dhttp://www4c.wolframalpha.com/Calculate/MSP/MSP15221a13hh36a69i0df100003gi12aabhd746hb7?MSPStoreType=image/gif&s=4&w=472&h=1028
@Arnab09 :have u just write that now and upload it now !??????
yep..
WOW,that was Extremely fast !!!!!!
maybe.. :/
thanx, BTW
u got it? @calyne??
your welcome :)
y = ln(e^[-x] + xe^[-x]) y=-x( ln (e))+xe^(-x)=-x+xe^(-x) =x(e(-x)-1) dy/dx = x(-e(-x))+(e(-x)-1)
and for ur info ln e =1
idk how u got the second step, @dhashni
applying logarithm simplification ln(e^(-x))=-xlne=-x
yeah, but the second part.. u cant get the term after + sign out of log
yeah i made a blunder mistake !!!!
|dw:1334424165372:dw|
|dw:1334424204454:dw|
i.e: -x+ln(1+x), nice..
|dw:1334424237437:dw|

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