Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

A prism has a right triangle as its base with a hypotenuse that measures 5 meters and legs that measure 3 meters and 4 meters. What is the surface area of this prism if the height of the prism is 6 meters? 78 m^2 84 m^2 96 m^2 102 m^2

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

I suck at drawing lol so the problem says that the sides of the triangle are 5,3 and 4 and the height is 6 And we are asked to look for the surface area If you would get the "pieces" of the prism you would get....2 bases (which are triangles) and 3 sides (which are rectangles) the formula for the surface area is 2B+Ph B= area of base (triangle) P=perimeter of base (triangle) h=height There are three sides given for the triangle at the base (3 and 4 as the legs) (and 5 as the hypotenuse) In any triangle, If the side lengths are known then the area of the triangle can be calculated using heron's formula A= sqrt (S*(S-a)(S-b)(s-c) where s is the semi perimeter (meaning half of the perimeter) S=(a+b+c)/2 We need to find s first a=3 b=4 c=5 (3+4+5)/2 12/2 4 Then use that for the equation A= sqrt (S*(S-a)(S-b)(s-c) A=sqrt(6(6-3)((6-4)(6-5) = sqrt ((6(3)(2)(1) sqrt (36) =6 B=6 Now this is the area of the base Now we get the perimeter of the triangle and multiply it by the height The perimeter is the sum of all the sides P=a+b+c =3+4+5 12 then multiply it by 6 (which is the height 12(6) 72 Now back to the equation 2B+Ph SA=2(6) +72 Sa=12+72 =84 :D

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question