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juanjohnguy

  • 4 years ago

Integral help! I'm just not seeing how to start to solve this integral.....its the integral of (ln(x+3))/(x+3)

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  1. freckles
    • 4 years ago
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    did you try letting u=ln(x+3)

  2. juanjohnguy
    • 4 years ago
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    then what would make the (x+3) on the bottom?

  3. freckles
    • 4 years ago
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    \[\int\limits_{}^{}\ln(x+3) \cdot \frac{1}{x+3} dx\] \[u=\ln(x+3) => du=\frac{1}{x+3} dx\]

  4. freckles
    • 4 years ago
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    Now just make those replacements and you will have something easy to integrate

  5. juanjohnguy
    • 4 years ago
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    oh! herp derp to myself

  6. freckles
    • 4 years ago
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    :) I'm glad I could be a service

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