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juanjohnguy
Integral help! I'm just not seeing how to start to solve this integral.....its the integral of (ln(x+3))/(x+3)
did you try letting u=ln(x+3)
then what would make the (x+3) on the bottom?
\[\int\limits_{}^{}\ln(x+3) \cdot \frac{1}{x+3} dx\] \[u=\ln(x+3) => du=\frac{1}{x+3} dx\]
Now just make those replacements and you will have something easy to integrate
oh! herp derp to myself
:) I'm glad I could be a service