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Al locker combination uses three digits, without repetition, of the digits 0-9. What is the probability that Chris will choose the correct combination on his first attempt to open the locker?

  • 2 years ago
  • 2 years ago

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  1. eigenschmeigen
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    as we choose the first number, we have 10 options, since we cant repeat, the second number has 9 options and the third has 8 options 10*9*8 possible combinations so if he chooses completely at random we have 1/(10*9*8)

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  2. Soni-kay
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    Thank you

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