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Soni-kay

  • 2 years ago

To use a school copier, a 4- digit code using the digits 0-9 must be entered. If each code cannot begin with the number 0 and there are 81 acceptable codes, what is the probability that someone will randomly select a usable code?

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  1. satellite73
    • 2 years ago
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    \(\frac{1}{81}\)??

  2. philips13
    • 2 years ago
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    how many four digit numbers are there?

  3. Soni-kay
    • 2 years ago
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    does not say

  4. philips13
    • 2 years ago
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    number acceptable ---------------- will be the answer total number

  5. philips13
    • 2 years ago
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    sure it does... use four digits, 0 to 9.... how many possible codes are there?

  6. Soni-kay
    • 2 years ago
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    i got one

  7. philips13
    • 2 years ago
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    let's see... 0000 0001 0002 0003 0004 ... 9999 so there are how many possible codes?

  8. Soni-kay
    • 2 years ago
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    when u divide

  9. Soni-kay
    • 2 years ago
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    81/10,000

  10. philips13
    • 2 years ago
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    that looks right to me

  11. philips13
    • 2 years ago
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    probability questions usually boil down to number of good ways / number of all the ways

  12. Soni-kay
    • 2 years ago
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    thank you

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