anonymous
  • anonymous
To use a school copier, a 4- digit code using the digits 0-9 must be entered. If each code cannot begin with the number 0 and there are 81 acceptable codes, what is the probability that someone will randomly select a usable code?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
\(\frac{1}{81}\)??
anonymous
  • anonymous
how many four digit numbers are there?
anonymous
  • anonymous
does not say

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anonymous
  • anonymous
number acceptable ---------------- will be the answer total number
anonymous
  • anonymous
sure it does... use four digits, 0 to 9.... how many possible codes are there?
anonymous
  • anonymous
i got one
anonymous
  • anonymous
let's see... 0000 0001 0002 0003 0004 ... 9999 so there are how many possible codes?
anonymous
  • anonymous
when u divide
anonymous
  • anonymous
81/10,000
anonymous
  • anonymous
that looks right to me
anonymous
  • anonymous
probability questions usually boil down to number of good ways / number of all the ways
anonymous
  • anonymous
thank you

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