Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

elica85

  • 4 years ago

find eigenvector for eigenvalue -2...

  • This Question is Closed
  1. elica85
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    after i plug in the value, i have the matrix |dw:1334524320293:dw|

  2. elica85
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    multiplied 1st row by 2 and add to second row, multiply 1st row by -2 and add to 3rd row... |dw:1334524445998:dw|

  3. elica85
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    multiply second row by -1/2 and add to 3rd row... |dw:1334524531744:dw|

  4. elica85
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so now i have these equations v1+v2+2v3=0 -2v2+2v3=0 -6v3=0

  5. elica85
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i'm not sure what the vector is, if v3=0, then -2v2+2(0)=0 so v2 must be 0 also and then v1+0+0=0 would mean v1 is zero too, right?

  6. myko
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but that's what you wanted |A-I(Lambda)| =0

  7. myko
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    just put any value, for example v3=a and find the other

  8. elica85
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    well for other eigenvalues, i have vectors with nonzero values...ok, if i plug in 3for v3, the last equation wouldn't make sense. and the answer isn't 0 vector. the vectors i have for my other values are correct

  9. phi
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    you should get a singular matrix the last row should be 0

  10. myko
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    -2v2+2a=0 v2=a v1+v2+2v3=0 v1+a+2a=0 v1 = -3a eigenvector (1,1,3)

  11. elica85
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it doesn't have to be all 0

  12. myko
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @phi is right the matrix should be singular. So you made a mistake somewhere

  13. myko
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |A-I(Lambda)| =0

  14. phi
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    remember you are solving det(A- lambda*I)= 0

  15. elica85
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i was taught the bottom left triangle has to be 0s.

  16. elica85
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so it would be the bottom left corner, and the values right above and to the right

  17. myko
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    the determinant has to be 0

  18. elica85
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i've checked and checked to see if i made a mistake...i will look again

  19. phi
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 2

    what is the original matrix?

  20. myko
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i think your eigenvalue is wrong

  21. elica85
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ugh idiot i did do it wrong. value is right, i will rework this

  22. myko
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    just trying to help

  23. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy