\[(x/9+1/3+1/x)/(x ^{2}/9-3/x)\] Kill the baby fractions in this problem

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\[(x/9+1/3+1/x)/(x ^{2}/9-3/x)\] Kill the baby fractions in this problem

Mathematics
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\[\huge{\frac x9+\frac13+\frac1x\over\frac{x^2}9-\frac3x}\]right?
sounds like a morbid carnival game
lol

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if your problem is as I posted it I would multiply by\[{9x\over9x}\]for starters
yea, that's the problem
then read the above post^^^^
Yes I did that. Leaving you with 1/3 + 1/x on the top and x - 3/x on the bottom.
I don't think you did it quite carefully enough since we didn't kill all the fractions.

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