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anonymous
 4 years ago
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anonymous
 4 years ago
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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0calculate this limit \[\lim_{x \rightarrow 2^{+}}\sqrt{x2}\]

apoorvk
 4 years ago
Best ResponseYou've already chosen the best response.1aah so you have a question, sorry, will solve it then.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0zero from your eyes replace x by 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then see if this one exists \[\lim_{x \rightarrow 2^{}}\sqrt{x2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no because the domain of \(\sqrt{x2}\) is \(x\geq 2\) so you cannot replace x by values less than 2

apoorvk
 4 years ago
Best ResponseYou've already chosen the best response.1well, for 2+, limit exists. put just replace the x=2+ (since we do not have to overcome any indeterminant form) now 2+ is basically a no. a very wee bit larger than 2. that is about... "2.000000...001" so square root of (0.0000000...0001) is almost negligible, that is zero. So, '0'.

apoorvk
 4 years ago
Best ResponseYou've already chosen the best response.1LHL of 2+ is 2. RHL is a wee bit more that 2.000...001, you can say 2.000....002

apoorvk
 4 years ago
Best ResponseYou've already chosen the best response.1so when 2 isnt coming into the picture, so we don't have a prob there with domain or what lies under the square root. You're welcome

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yup. thank u. i think the person tha wrote the answers to this exercise list was on crack.

apoorvk
 4 years ago
Best ResponseYou've already chosen the best response.1Oh sorry I didn't see the other question you had posted, I was only explaining the earlier problem. wait.

apoorvk
 4 years ago
Best ResponseYou've already chosen the best response.1In the second problem, Limit doesnt exist, exactly for the same reasons that they do in the first problem

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah, thats the answer i got, but here it says the limit is 1. This professor is mental lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0doesn't know how to type

apoorvk
 4 years ago
Best ResponseYou've already chosen the best response.1nope, limit can't be possibly one. there may have been a printing or typing error, not necessarily your prof's fault.

TuringTest
 4 years ago
Best ResponseYou've already chosen the best response.0this is like the fifth problem I've seen of yours with the incorrect answer I feel for you :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0seee, everytime i think i'm going crazy..but thank you guys, AGAIN.
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