Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

jadefalcon

  • 2 years ago

Calculate the time required to send a 56 byte packet from Sydney to Melbourne if the data rate is155mbps, the distance traveled is 1000km and the speed of propagation is 2.8*10^8m/s.

  • This Question is Closed
  1. CeW
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Let's say the packet starts being transmitted at t=0. The propagation time is d/c = 1000e3/2.8e8 = 3.5714e-3 seconds. This is when the leading edge of the packet just starts arriving at the receiver. The duration of the packet is 56 / 115e6 = 4.87e-7 seconds. The entire packet will have arrived at the receiver at the sum of these two times, or 3.5719 msec.

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.