28Tylerr
Find the sum of the measures of the interior angles of each convex polygon.
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luck4u
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overall
28Tylerr
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Here is the question: 16-gon
luck4u
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???
luck4u
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i dont know
28Tylerr
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It wants me to find the sum of a convex polygon and the polygon is a 16-gon
28Tylerr
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& I can't seem to figure it out.
.Sam.
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Use the formula (n-2)*180
28Tylerr
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Ok, So would it be 16 in place of the n?
.Sam.
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You will get 2520 degrees
28Tylerr
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Ok, But what number would I put in place of the n?
.Sam.
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16
28Tylerr
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Alright thanks man, Can ya help me with a couple of more?
.Sam.
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ok
28Tylerr
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My next one is: The measure of the interior angles of a regular polygon is given. Find the number of sides in the polygon.
28Tylerr
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Here is the question: 1980.
.Sam.
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Sum of the angles is 1980?
28Tylerr
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I just got to find the polygon that has a number of sides of 1980.
28Tylerr
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Thats basically what it is.
28Tylerr
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..Sam, Can ya help?
.Sam.
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\[\frac{(n-2)\times180}{n}=\text{Each \angle inside the polygon}\]
\[(n-2)\times180=\text{Sum of angles inside the polygon}\]
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So,
\[(n-2)\times180=\text{Sum of angles inside the polygon}\]
\[(n-2)\times180=1980\]
n=13
28Tylerr
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Alright thanks, Can ya help with 4 more lol? Sorry man
.Sam.
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post as a new question
28Tylerr
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Alright, Give me a min
SmoothMath
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The equation is (180)(n-2), where n is the number of sides. Here's why:
|dw:1334620067825:dw|
The number of triangles that I can split the polygon up into, is n-2. Each triangle's interior angles sum to 180. How cool! =D