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TVo_12

  • 4 years ago

Did I do this right: (x-5y) (x-5y) x^2-5xy-5xy+25 should this be my answer; x^2-10xy+25

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  1. DoomDude
    • 4 years ago
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    yes

  2. DoomDude
    • 4 years ago
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    wait...

  3. DoomDude
    • 4 years ago
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    x^2 -10xy+25y^2 right?

  4. math456
    • 4 years ago
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    do like x(x-5y)-5y(x-5y) x^2-5xy-5xy+25y^2 x^2-10xy+25y^2

  5. DoomDude
    • 4 years ago
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    ya...

  6. TVo_12
    • 4 years ago
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    teacher said to write it twice.

  7. math456
    • 4 years ago
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    there should be y^2 in 25

  8. DoomDude
    • 4 years ago
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    when you do 5y x 5y the two "y" are doubled

  9. TVo_12
    • 4 years ago
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    how

  10. DoomDude
    • 4 years ago
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    because you are multiplying the fives, and the y's

  11. math456
    • 4 years ago
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    i did it, have a look @TVo_12

  12. radar
    • 4 years ago
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    5y times 5y is 25y^2

  13. math456
    • 4 years ago
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    x(x-5y)-5y(x-5y) x^2-5xy-5xy+25y^2 x^2-10xy+25y^2

  14. DoomDude
    • 4 years ago
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    indeed it is

  15. TVo_12
    • 4 years ago
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    thanks

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