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adeniyta

  • 2 years ago

Hey- could someone please help me with the free body diagrams. If there is a hand pushing on a book,laying on a table- what are the forces acting on the book? I thought they were normal force, force of hand and gravity.

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  1. eashmore
    • 2 years ago
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    Consider the presence of a friction force as well. It will be directed opposite the force of the hand. Otherwise, the three you named is it.

  2. adeniyta
    • 2 years ago
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    Will there be friction, if the hand is acting upon the book from above?

  3. UnkleRhaukus
    • 2 years ago
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    |dw:1334633188981:dw|

  4. adeniyta
    • 2 years ago
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    Okay thank you this was very helpful.

  5. adeniyta
    • 2 years ago
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    If the book is being pushed up a wall what forces would affect the book? Here is what I think?

  6. adeniyta
    • 2 years ago
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    |dw:1334634207666:dw|

  7. eashmore
    • 2 years ago
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    Gravity does not act on the book in the horizontal direction. If the applied force is vertical, there will be no normal force between the book and the wall and thereby no friction force. |dw:1334635152412:dw|

  8. adeniyta
    • 2 years ago
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    Isn't there friction because there are two surfaces in contact with each other?

  9. quarkine
    • 2 years ago
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    yeah but only is when surfaces are moving wrt each other..

  10. eashmore
    • 2 years ago
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    From Coulomb's Friction model, there must be a normal force present between the two. In this basic case, there is no normal force between the wall and the book and therefore, no friction force.

  11. eashmore
    • 2 years ago
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    Coulomb's friction model is\[F_f = mu N\]

  12. eashmore
    • 2 years ago
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    We can't simply create a normal force because we desire to have friction.

  13. adeniyta
    • 2 years ago
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    Hmm.... this is interesting that's seems kind of strange, but I understand it.

  14. adeniyta
    • 2 years ago
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    I have one more quick question (thank you for your patience): If there are for links connected together and are suspended by a rope. Here is what I thinks and a picture:

  15. adeniyta
    • 2 years ago
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    |dw:1334636071637:dw|

  16. adeniyta
    • 2 years ago
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    The force on 1= tension of rope and weight of rings 2,3 and 4. The force on 2= tension caused by chain link 2 and force of weight of 3 and 4. The force on 3 = tension caused by chain links 1 and 2 and weight of 4. The force on 4= tension caused by chain links 1,2 and 3 and force of gravity.

  17. eashmore
    • 2 years ago
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    Indeed. Realize that tension of the rope must equal the weight of all four ring if the links aren't moving.

  18. adeniyta
    • 2 years ago
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    k- good I think I get the concept. Thank you a ton- you are very patient.

  19. eashmore
    • 2 years ago
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    You're very welcome!

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