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Flapdragon
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If the diameter of a circle has endpoints P(–10, –2) and Q(4, 6), where is the center of the circle, how long is its radius, and what is the equation for the circle?
 2 years ago
 2 years ago
Flapdragon Group Title
If the diameter of a circle has endpoints P(–10, –2) and Q(4, 6), where is the center of the circle, how long is its radius, and what is the equation for the circle?
 2 years ago
 2 years ago

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Rohangrr Group TitleBest ResponseYou've already chosen the best response.2
The center is the midpoint of a diameter so use the midpoint formula. C = ([10 + 4]/2, [8 + 4]/2) C = (3, 2) Then use distance formula to get the radius (use either diameter endpoint) r = √( [4  3]^2 + [4  2]^2) = √(7^2 + 6^2) = √(49 + 36) = √85 The equation of a circle with center (h,k) and radius r is (x  h)^2 + (y  k)^2 = r^2 so (x + 3)^2 + (y + 2)^2 = 85
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
the radius would be half the distance of the diameter...you do know how to do the distance formula right? do the distance formula..that's your diameter..divide it by 2 that's your radius.. as for the center..it's the midpoint of your diameter
 2 years ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.1
seems to be a problem with the centre, in particular the y value
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
the equation of the circle is just combine all the gathered information from the coordinates of the center and the length of the radius...do you need further hints? @Flapdragon ?
 2 years ago

Flapdragon Group TitleBest ResponseYou've already chosen the best response.0
Thank you! c: It's fine.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
glad to help <tips hat>
 2 years ago

Rohangrr Group TitleBest ResponseYou've already chosen the best response.2
myplesure og helping u
 2 years ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.1
I think the centre is x (10 + 4)/2 = 3 y = (2 + 6)/2 = 2 centre is (3, 2) radius = \[\sqrt{(10 +3)^2 (2 2)^2} = \sqrt{49 + 16} = \sqrt{65}\] so the equation of the circle is (x +3)^2 + (y 2)^2 = 65
 2 years ago
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