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SmartOwl94
Group Title
Choose the equation for the hyperbola centered at the origin with the given characteristics.
1.one focus (0, square root of 34), one vertex (0, 5)
2.vertical transverse axis, b = 6, c = square root of 45
3.vertices (+2, 0), perimeter of central rectangle 24 units
 2 years ago
 2 years ago
SmartOwl94 Group Title
Choose the equation for the hyperbola centered at the origin with the given characteristics. 1.one focus (0, square root of 34), one vertex (0, 5) 2.vertical transverse axis, b = 6, c = square root of 45 3.vertices (+2, 0), perimeter of central rectangle 24 units
 2 years ago
 2 years ago

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SmartOwl94 Group TitleBest ResponseYou've already chosen the best response.0
I have multiple choice selections for these problems
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
The equation of a hyperbola that opens up/down (north/south) is \[ \frac{y^2}{a^2} \frac{x^2}{b^2} =1 \] I remember that the y term goes first with "Y the smile? Y the frown?" For 1.one focus (0, square root of 34), one vertex (0, 5) we can plot these points dw:1334667585835:dw so we know we are looking for \[ \frac{y^2}{a^2} \frac{x^2}{b^2} =1 \]
 2 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
You should know that the vertex is "a" away from the center (0,0), so a=5 and a^2=25 we also need to know that the focus (call it c) is defined by \[c^2= a^2+b^2 \] They give us c= sqrt(34), so c^2 =34. we can now find b: 34= 25+b^2 b^2=9 and b=3 so the equation should be \[ \frac{y^2}{25} \frac{x^2}{9} =1 \]
 2 years ago
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