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Three marbles are to be drawn successively from a bag that contains 4 red marbles, 2 blue marbles, and 3 green marbles. No replacement is done. What is the probability that the first marble drawn is red, the second is blue and the third is green?
 one year ago
 one year ago
Three marbles are to be drawn successively from a bag that contains 4 red marbles, 2 blue marbles, and 3 green marbles. No replacement is done. What is the probability that the first marble drawn is red, the second is blue and the third is green?
 one year ago
 one year ago

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KingGeorgeBest ResponseYou've already chosen the best response.3
You have \(4+2+3=9\) total marbles. Thus, the probability you would get a red marble is given by \(4/9\) since you can choose 4 marbles from 9. Now, we've removed a ball, so there are 8 balls left. Here, the chance to draw a blue marble would be \(2/8\) since you can choose two marbles from 8. Likewise, choosing a green marble now would be \(3/7\) for similar reasoning. Thus, your final answer should be \[{4 \over 9}\cdot{2 \over 8}\cdot{3 \over 7}\]
 one year ago
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