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anonymous
 4 years ago
For the equation find the equation of the graph that is parallel and perpendicular that passes through the specified point. Then graph the equations
The equation is 3x  y = 9
So i have the equations
y = 3x + 9
y = 3x  2
y = 1/3x + 4/3
but I am confused on how to graph it
anonymous
 4 years ago
For the equation find the equation of the graph that is parallel and perpendicular that passes through the specified point. Then graph the equations The equation is 3x  y = 9 So i have the equations y = 3x + 9 y = 3x  2 y = 1/3x + 4/3 but I am confused on how to graph it

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.03x  y = 9 so y = 3x9 perpendicular: y =1/3x 9

2bornot2b
 4 years ago
Best ResponseYou've already chosen the best response.1@MSFFL the equation for perpendicular line, that you have prepared is incorrect, to the best of my knowledge.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I got the 3 equation by doing the following The specified points are (1,1) 1. 3x  y = 9 2. y = 3x + 9 3. y = 3x 9 (Slope = 3) So now 1. y = mx+b 2. 1 = 3(1) + b 3. b = 2 Equation is y = 3x  2 for perpendicular Slope = 1/3 1. y = mx + b 2. 1 = 1/3(1) + b 3. b = 4/3 Equation is y = 1/3x + 4/3

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now how do I graph it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0slope m means : for 1 horizontal unit you go up m vertical units the last term in y = mx + b equation, b, is the point where you intersect y axis
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