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For the equation find the equation of the graph that is parallel and perpendicular that passes through the specified point. Then graph the equations
The equation is 3x  y = 9
So i have the equations
y = 3x + 9
y = 3x  2
y = 1/3x + 4/3
but I am confused on how to graph it
 one year ago
 one year ago
For the equation find the equation of the graph that is parallel and perpendicular that passes through the specified point. Then graph the equations The equation is 3x  y = 9 So i have the equations y = 3x + 9 y = 3x  2 y = 1/3x + 4/3 but I am confused on how to graph it
 one year ago
 one year ago

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mykoBest ResponseYou've already chosen the best response.0
3x  y = 9 so y = 3x9 perpendicular: y =1/3x 9
 one year ago

2bornot2bBest ResponseYou've already chosen the best response.1
@MSFFL the equation for perpendicular line, that you have prepared is incorrect, to the best of my knowledge.
 one year ago

MSFFLBest ResponseYou've already chosen the best response.0
I got the 3 equation by doing the following The specified points are (1,1) 1. 3x  y = 9 2. y = 3x + 9 3. y = 3x 9 (Slope = 3) So now 1. y = mx+b 2. 1 = 3(1) + b 3. b = 2 Equation is y = 3x  2 for perpendicular Slope = 1/3 1. y = mx + b 2. 1 = 1/3(1) + b 3. b = 4/3 Equation is y = 1/3x + 4/3
 one year ago

mykoBest ResponseYou've already chosen the best response.0
slope m means : for 1 horizontal unit you go up m vertical units the last term in y = mx + b equation, b, is the point where you intersect y axis
 one year ago

2bornot2bBest ResponseYou've already chosen the best response.1
Here are the graphs,
 one year ago
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