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MSFFL
Group Title
For the equation find the equation of the graph that is parallel and perpendicular that passes through the specified point. Then graph the equations
The equation is 3x  y = 9
So i have the equations
y = 3x + 9
y = 3x  2
y = 1/3x + 4/3
but I am confused on how to graph it
 2 years ago
 2 years ago
MSFFL Group Title
For the equation find the equation of the graph that is parallel and perpendicular that passes through the specified point. Then graph the equations The equation is 3x  y = 9 So i have the equations y = 3x + 9 y = 3x  2 y = 1/3x + 4/3 but I am confused on how to graph it
 2 years ago
 2 years ago

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myko Group TitleBest ResponseYou've already chosen the best response.0
3x  y = 9 so y = 3x9 perpendicular: y =1/3x 9
 2 years ago

2bornot2b Group TitleBest ResponseYou've already chosen the best response.1
@MSFFL the equation for perpendicular line, that you have prepared is incorrect, to the best of my knowledge.
 2 years ago

MSFFL Group TitleBest ResponseYou've already chosen the best response.0
I got the 3 equation by doing the following The specified points are (1,1) 1. 3x  y = 9 2. y = 3x + 9 3. y = 3x 9 (Slope = 3) So now 1. y = mx+b 2. 1 = 3(1) + b 3. b = 2 Equation is y = 3x  2 for perpendicular Slope = 1/3 1. y = mx + b 2. 1 = 1/3(1) + b 3. b = 4/3 Equation is y = 1/3x + 4/3
 2 years ago

MSFFL Group TitleBest ResponseYou've already chosen the best response.0
Now how do I graph it?
 2 years ago

myko Group TitleBest ResponseYou've already chosen the best response.0
slope m means : for 1 horizontal unit you go up m vertical units the last term in y = mx + b equation, b, is the point where you intersect y axis
 2 years ago

2bornot2b Group TitleBest ResponseYou've already chosen the best response.1
Here are the graphs,
 2 years ago
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