anonymous
  • anonymous
Please help me
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
\[a^2+b^2=c^2\]
anonymous
  • anonymous
"Ty

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More answers

jhonyy9
  • jhonyy9
7*5=35
anonymous
  • anonymous
Ty
anonymous
  • anonymous
nay \[7^2+2^2=c^2\]
anonymous
  • anonymous
\[\sqrt{c^2}=PU\]
anonymous
  • anonymous
53 square
anonymous
  • anonymous
now throw a square root on there and you get the distance P-U \[\sqrt{53}\]
anonymous
  • anonymous
i meesed this one up :\
anonymous
  • anonymous
no, \[53 = c^2\]
anonymous
  • anonymous
i wanna try another
anonymous
  • anonymous
i put the wrong thing in and ir markd it wrong
anonymous
  • anonymous
Start a new Q for medal sakes
anonymous
  • anonymous
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jhonyy9
  • jhonyy9
- so area of parallelogramm is 35 sq mi
anonymous
  • anonymous
Huh?
anonymous
  • anonymous
Put this in a new Q Zyaira
anonymous
  • anonymous
And label it accordingly :)
anonymous
  • anonymous
Cant you just solve it here?
anonymous
  • anonymous
I can, but if someone else can solve it, they might like the chance at earning your medal...
anonymous
  • anonymous
Cmon lets help make this site work the way its supposed to
anonymous
  • anonymous
ok

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