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How would i solve the following question? A 14.8kg child sits in a 1.30kg swing. You pull the swing back, lifting it 52.1cm vertically, and let go. Determine the speed of the child and swing as the swing moves past its lowest point.

Physics
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what formula would i use?
1/2mv^2= mgh
You can use law of conservation of energy. Initially, P.Ei = 0, K.Ei = 0. then, P.Ef = mgh K.Ef = ? P.Ei + K.Ei = P.Ef + K.Ef 0 = mgh + K.Ef you can find K.Ef and hence velocity.

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Other answers:

I would use conservation of energy. \[mgh = {1 \over 2} mv^2\] where h is the height the child is raised (the lowest point of the swing is our reference point for potential energy, not the surface of the earth, I can explain this further if you don't fully understand.) and v will be the velocity at this lowest point.
my ans contd.. m cancels out itself so\[V=\sqrt{2gh}\]

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