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Blooper9671111

  • 3 years ago

How would i solve the following question? A 14.8kg child sits in a 1.30kg swing. You pull the swing back, lifting it 52.1cm vertically, and let go. Determine the speed of the child and swing as the swing moves past its lowest point.

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  1. Blooper9671111
    • 3 years ago
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    what formula would i use?

  2. ujjwal
    • 3 years ago
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    1/2mv^2= mgh

  3. shubham
    • 3 years ago
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    You can use law of conservation of energy. Initially, P.Ei = 0, K.Ei = 0. then, P.Ef = mgh K.Ef = ? P.Ei + K.Ei = P.Ef + K.Ef 0 = mgh + K.Ef you can find K.Ef and hence velocity.

  4. eashmore
    • 3 years ago
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    I would use conservation of energy. \[mgh = {1 \over 2} mv^2\] where h is the height the child is raised (the lowest point of the swing is our reference point for potential energy, not the surface of the earth, I can explain this further if you don't fully understand.) and v will be the velocity at this lowest point.

  5. ujjwal
    • 3 years ago
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    my ans contd.. m cancels out itself so\[V=\sqrt{2gh}\]

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