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anonymous
 4 years ago
Will a precipitate form if 100ml of 1.0x10^3 mol/L Pb(NO3)2 solution is added to 100ml of 2.0x10^3 mol/L MgSO4 solution?
anonymous
 4 years ago
Will a precipitate form if 100ml of 1.0x10^3 mol/L Pb(NO3)2 solution is added to 100ml of 2.0x10^3 mol/L MgSO4 solution?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Callisto can you help me?

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.1Yes... PbSO4 is insoluble

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.1\[Pb(NO_{3})_{2} (aq) + MgSO_{4} (aq) > PbSO_{4}(s) + Mg^{2+}(aq) + 2NO_{3} ^{}(aq)\]

mos1635
 4 years ago
Best ResponseYou've already chosen the best response.0if Ksp of PbSO4 is given we could have a more acurate investigation.....

JFraser
 4 years ago
Best ResponseYou've already chosen the best response.1a ppt may or may not form, it depends on the concentrations. Ksp calculations will determine whether the combination of ions is concentrated enough to give a ppt.

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.1I'm sorry!!! I haven't learnt anything about Ksp ... so I don't know that ppt may not form ... I'm sorry...

JFraser
 4 years ago
Best ResponseYou've already chosen the best response.1@Callisto you are generally correct, a ppt will probably form because PbSO4 is insoluble, but if the concentrations are weak enough, there won't be a ppt

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.1@JFraser Thank you for giving more information. Consider this case, would there be any ppt?

JFraser
 4 years ago
Best ResponseYou've already chosen the best response.1give me a few minutes to work through the numbers, i have to go teach soon

JFraser
 4 years ago
Best ResponseYou've already chosen the best response.1in this case,a ppt will not form. the concentration of the combined ions is less than the maximum allowable by the KSP

Callisto
 4 years ago
Best ResponseYou've already chosen the best response.1Sorry again.. I know I have no right to ask, but can you show how you get the answer?
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