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Will a precipitate form if 100ml of 1.0x10^3 mol/L Pb(NO3)2 solution is added to 100ml of 2.0x10^3 mol/L MgSO4 solution?
 one year ago
 one year ago
Will a precipitate form if 100ml of 1.0x10^3 mol/L Pb(NO3)2 solution is added to 100ml of 2.0x10^3 mol/L MgSO4 solution?
 one year ago
 one year ago

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JoBoBest ResponseYou've already chosen the best response.0
@Callisto can you help me?
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
Yes... PbSO4 is insoluble
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
\[Pb(NO_{3})_{2} (aq) + MgSO_{4} (aq) > PbSO_{4}(s) + Mg^{2+}(aq) + 2NO_{3} ^{}(aq)\]
 one year ago

mos1635Best ResponseYou've already chosen the best response.0
if Ksp of PbSO4 is given we could have a more acurate investigation.....
 one year ago

JFraserBest ResponseYou've already chosen the best response.1
a ppt may or may not form, it depends on the concentrations. Ksp calculations will determine whether the combination of ions is concentrated enough to give a ppt.
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
I'm sorry!!! I haven't learnt anything about Ksp ... so I don't know that ppt may not form ... I'm sorry...
 one year ago

JFraserBest ResponseYou've already chosen the best response.1
@Callisto you are generally correct, a ppt will probably form because PbSO4 is insoluble, but if the concentrations are weak enough, there won't be a ppt
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
@JFraser Thank you for giving more information. Consider this case, would there be any ppt?
 one year ago

JFraserBest ResponseYou've already chosen the best response.1
give me a few minutes to work through the numbers, i have to go teach soon
 one year ago

JFraserBest ResponseYou've already chosen the best response.1
in this case,a ppt will not form. the concentration of the combined ions is less than the maximum allowable by the KSP
 one year ago

CallistoBest ResponseYou've already chosen the best response.1
Sorry again.. I know I have no right to ask, but can you show how you get the answer?
 one year ago
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