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Aadarsh
 3 years ago
I have a doubt in Light chapter. Please help.
Aadarsh
 3 years ago
I have a doubt in Light chapter. Please help.

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Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0Kindly answer the "Exercise" Question. I have tried this way. Kindly check whether it is correct.

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0Apparent Depth = dw:1334728666632:dw = 50/(4/3) + 10(1.5) = 37.5 + 6.33

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0Shift = dw:1334728756502:dw = 50 [ 1  {1/(4/3}] + 10 [ 1 {1/1.5}]

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0@Mani_Jha bhai, please help.

Ishaan94
 3 years ago
Best ResponseYou've already chosen the best response.0I'll be back in a moment.

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0@apoorvk bhai, please try.

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.0One sec, which medium is optically denser  glass or water? Did you account for that?

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0@srinidhijha bhai, @wasiqss bhai, please help.

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.0@Aadarsh mu1 and mu2 need to be checked. Mu values change when you are travelling from water to glass or viceversa instead of air to glass. because in the formula, we consider the "relative mu"

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, I want to know whether I am rite or wrong.

fretje
 3 years ago
Best ResponseYou've already chosen the best response.3my god, what courses do you have: there are syntax errors in the questions: Find the apparent depth and apparent shift of an object placed at the bottom of the a vessel containing a glass slab of thickness 10 cm and water of height 50cm. as shown in the figure. > what is : at the bottom of the a vessel, it's like reading shakespeare. But ok, i can understand the question, but i don't see the picture. Can you rescan it?

fretje
 3 years ago
Best ResponseYou've already chosen the best response.3Or were you scanning the page just to show the error?

fretje
 3 years ago
Best ResponseYou've already chosen the best response.3OK, so assuming the next situation:

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0@fretje , ur diagram is correct now. The question is correct now. I got that formulae from the study material which contains these questions.

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0@salini , @Ruchi. , @Sarkar please help me and post the answer.

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, but can u explai me @Ruchi. ?? Please. Whether i am correct/

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0@neha2050 diid, please try.

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0@rockstar111 please try.

neha2050
 3 years ago
Best ResponseYou've already chosen the best response.0mujh to question hi smj me nhi aa rha hai kya .

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0O @neha2050 didi, koshish kijiye. Samajh mein aayega.

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.0Aadarsh tumhe sawaal samajh mein nahi aa raha, use solve karna nnahi aa raha, ya answers nahi aa rahe?

Aadarsh
 3 years ago
Best ResponseYou've already chosen the best response.0Mujhe answers check karna hai bas!!

apoorvk
 3 years ago
Best ResponseYou've already chosen the best response.0Okay, I 'll solve it, and get back to you on this.

fretje
 3 years ago
Best ResponseYou've already chosen the best response.3@aadarsh when is your deadline?

salini
 3 years ago
Best ResponseYou've already chosen the best response.0u can calculate apparent depth of the object from r.i(mui)=real depth /apparent depth the only issue here being that you will be taking r.i of glass with respect to water by apparent shift wat do u mean ?