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animaBest ResponseYou've already chosen the best response.0
this is the NAND operation for the que above...please someone help
 one year ago

dumbcowBest ResponseYou've already chosen the best response.0
not sure what "bar" represents is this boolean algebra ?
 one year ago

RomeroBest ResponseYou've already chosen the best response.0
Can you rewrite it again.
 one year ago

arcticf0xBest ResponseYou've already chosen the best response.2
One way could be, to draw it out, convert into NAND equivalents and form the equations.
 one year ago

dumbcowBest ResponseYou've already chosen the best response.0
im stuck of course you could be fancy and negate the NAND resulting in original AND operation > xy +z' = [(xy)']' +z'
 one year ago

arcticf0xBest ResponseYou've already chosen the best response.2
I got xy(bar).z(whole bar), sorry i dont know how to put that in latex.
 one year ago

dumbcowBest ResponseYou've already chosen the best response.0
arctic is that NAND(x,y) and z' ? it wont work for all values of 1 x=y=z=1 yields xy+z' = 1 (xy)'z' = 0
 one year ago

arcticf0xBest ResponseYou've already chosen the best response.2
noh dw:1334738031932:dw
 one year ago

dumbcowBest ResponseYou've already chosen the best response.0
ahh i see, yes that would work :) good job
 one year ago

arcticf0xBest ResponseYou've already chosen the best response.2
@anima Do you know what are NAND equivalents for NOT, AND and OR gates?
 one year ago

arcticf0xBest ResponseYou've already chosen the best response.2
If you dont, check this http://en.wikipedia.org/wiki/NAND_logic Then substitute all the NAND forms given to you, then form the expression again. You will yield this.
 one year ago

arcticf0xBest ResponseYou've already chosen the best response.2
Another simpler way would be using, Boolean algebra and De Morgan's laws.
 one year ago
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