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anima

Rewrite the expression xy+z' in terms of bar and the NAND operation

  • one year ago
  • one year ago

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  1. anima
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    |dw:1334734679026:dw|

    • one year ago
  2. anima
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    this is the NAND operation for the que above...please someone help

    • one year ago
  3. dumbcow
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    not sure what "bar" represents is this boolean algebra ?

    • one year ago
  4. anima
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    if z=1,then z'=0

    • one year ago
  5. Romero
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    Can you rewrite it again.

    • one year ago
  6. arcticf0x
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    One way could be, to draw it out, convert into NAND equivalents and form the equations.

    • one year ago
  7. dumbcow
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    im stuck of course you could be fancy and negate the NAND resulting in original AND operation --> xy +z' = [(xy)']' +z'

    • one year ago
  8. arcticf0x
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    I got xy(bar).z(whole bar), sorry i dont know how to put that in latex.

    • one year ago
  9. dumbcow
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    arctic is that NAND(x,y) and z' ? it wont work for all values of 1 x=y=z=1 yields xy+z' = 1 (xy)'z' = 0

    • one year ago
  10. arcticf0x
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    noh |dw:1334738031932:dw|

    • one year ago
  11. anima
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    how did u get this?

    • one year ago
  12. dumbcow
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    ahh i see, yes that would work :) good job

    • one year ago
  13. arcticf0x
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    @anima Do you know what are NAND equivalents for NOT, AND and OR gates?

    • one year ago
  14. arcticf0x
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    If you dont, check this http://en.wikipedia.org/wiki/NAND_logic Then substitute all the NAND forms given to you, then form the expression again. You will yield this.

    • one year ago
  15. arcticf0x
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    Another simpler way would be using, Boolean algebra and De Morgan's laws.

    • one year ago
  16. anima
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    ya Thanx a lot!!!

    • one year ago
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