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animaBest ResponseYou've already chosen the best response.0
this is the NAND operation for the que above...please someone help
 2 years ago

dumbcowBest ResponseYou've already chosen the best response.0
not sure what "bar" represents is this boolean algebra ?
 2 years ago

RomeroBest ResponseYou've already chosen the best response.0
Can you rewrite it again.
 2 years ago

arcticf0xBest ResponseYou've already chosen the best response.2
One way could be, to draw it out, convert into NAND equivalents and form the equations.
 2 years ago

dumbcowBest ResponseYou've already chosen the best response.0
im stuck of course you could be fancy and negate the NAND resulting in original AND operation > xy +z' = [(xy)']' +z'
 2 years ago

arcticf0xBest ResponseYou've already chosen the best response.2
I got xy(bar).z(whole bar), sorry i dont know how to put that in latex.
 2 years ago

dumbcowBest ResponseYou've already chosen the best response.0
arctic is that NAND(x,y) and z' ? it wont work for all values of 1 x=y=z=1 yields xy+z' = 1 (xy)'z' = 0
 2 years ago

arcticf0xBest ResponseYou've already chosen the best response.2
noh dw:1334738031932:dw
 2 years ago

dumbcowBest ResponseYou've already chosen the best response.0
ahh i see, yes that would work :) good job
 2 years ago

arcticf0xBest ResponseYou've already chosen the best response.2
@anima Do you know what are NAND equivalents for NOT, AND and OR gates?
 2 years ago

arcticf0xBest ResponseYou've already chosen the best response.2
If you dont, check this http://en.wikipedia.org/wiki/NAND_logic Then substitute all the NAND forms given to you, then form the expression again. You will yield this.
 2 years ago

arcticf0xBest ResponseYou've already chosen the best response.2
Another simpler way would be using, Boolean algebra and De Morgan's laws.
 2 years ago
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