Can anyone solve this? (still not solved)

- anonymous

Can anyone solve this? (still not solved)

- jamiebookeater

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- anonymous

##### 1 Attachment

- anonymous

Yes, but it is too cumbersome.

- anonymous

i know -.-

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## More answers

- Shayaan_Mustafa

hi ZyairaBoyd :)
Is it regular pentagon?

- anonymous

Pretty sure.....

- Shayaan_Mustafa

it seems too. So just ignore EB and EC. As you know regular pentagon always have same sides and here one side is given that is 10cm. If it is regular pentagon then it must have all sides with 10cm. Right?
And area of regular pentagon is\[\large A=1.72x^2\]
substitute x=10cm\[\large A=1.72(10cm)^2\]\[\large A=1.72(100cm^2)\]\[\large A=172cm^2\]If and only if it is a regular pentagon. Otherwise it is wrong..

- anonymous

It's not a regular pentagon.

- anonymous

Ok.

- Shayaan_Mustafa

OK. Let us see if it is not a regular pentagon. Be with me.

- anonymous

Man got to go. See ya.

- Shayaan_Mustafa

@ZyairaBoyd Is that enough for you?

- anonymous

Huh? No....

- anonymous

- KingGeorge

They want you to solve this with triangles. First, notice that solving for triangle ECB is the easiest. It's just \[{1 \over2}\cdot 10\cdot 13=65\]

- anonymous

Yeah so i have to like do it one by one?

- katielong

i'll be 2 mins.. i can do it though and il give you a good method!!

- anonymous

I dont mind.

- KingGeorge

Then, since EB=EC=4, the areas of triangles EBA and triangle ECD are the same. and are given by \[{1 \over 2}\cdot 15\cdot 4=30\]Since there are two of these triangles, we have an area of 60.

- KingGeorge

Now we add \(60+65=125\) To get the overall area.

- anonymous

oh ok.

- KingGeorge

We have three triangles with area 65, 30, and 30. If we add them, we get 125.

- anonymous

Ty for breaking it down...you saved me alot of time.

- anonymous

theres another one just like that with 3 triangles

- anonymous

Did i do this right so far?

##### 1 Attachment

- KingGeorge

That looks correct to me.

- anonymous

ok so now all i have to do is add them all together correct?

- KingGeorge

Correct.

- anonymous

Ok.

- katielong

|dw:1334855745714:dw|
here you see i worked out all of the sides by doing some halving.
so...
you can see the top triangles are 4cmx7.5cm
to find the area times them which equals 30
if you notice, it now needs halving but 30 is the equivilant of the area of two of those triangles so you dont need to half it.
its the same with the 13cmx5cm triangle
13x5=65
then you need to finally find the area of the last one... which is the same as the first... so to find the area of the shape you need to do...
30+65+30=........answer.....=125!!!!!!!!!
hope it helped?

- anonymous

i got 22.

- anonymous

Ty @katielong

- katielong

no probss =)
do you understand it??

- anonymous

yes.

- anonymous

|dw:1334856366881:dw|

- anonymous

- KingGeorge

You're very welcome.

- katielong

youre welcommeeeee =)

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