anonymous
  • anonymous
Can anyone solve this? (still not solved)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
Yes, but it is too cumbersome.
anonymous
  • anonymous
i know -.-

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Shayaan_Mustafa
  • Shayaan_Mustafa
hi ZyairaBoyd :) Is it regular pentagon?
anonymous
  • anonymous
Pretty sure.....
Shayaan_Mustafa
  • Shayaan_Mustafa
it seems too. So just ignore EB and EC. As you know regular pentagon always have same sides and here one side is given that is 10cm. If it is regular pentagon then it must have all sides with 10cm. Right? And area of regular pentagon is\[\large A=1.72x^2\] substitute x=10cm\[\large A=1.72(10cm)^2\]\[\large A=1.72(100cm^2)\]\[\large A=172cm^2\]If and only if it is a regular pentagon. Otherwise it is wrong..
anonymous
  • anonymous
It's not a regular pentagon.
anonymous
  • anonymous
Ok.
Shayaan_Mustafa
  • Shayaan_Mustafa
OK. Let us see if it is not a regular pentagon. Be with me.
anonymous
  • anonymous
Man got to go. See ya.
Shayaan_Mustafa
  • Shayaan_Mustafa
@ZyairaBoyd Is that enough for you?
anonymous
  • anonymous
Huh? No....
anonymous
  • anonymous
@Shayaan_Mustafa
KingGeorge
  • KingGeorge
They want you to solve this with triangles. First, notice that solving for triangle ECB is the easiest. It's just \[{1 \over2}\cdot 10\cdot 13=65\]
anonymous
  • anonymous
Yeah so i have to like do it one by one?
katielong
  • katielong
i'll be 2 mins.. i can do it though and il give you a good method!!
anonymous
  • anonymous
I dont mind.
KingGeorge
  • KingGeorge
Then, since EB=EC=4, the areas of triangles EBA and triangle ECD are the same. and are given by \[{1 \over 2}\cdot 15\cdot 4=30\]Since there are two of these triangles, we have an area of 60.
KingGeorge
  • KingGeorge
Now we add \(60+65=125\) To get the overall area.
anonymous
  • anonymous
oh ok.
KingGeorge
  • KingGeorge
We have three triangles with area 65, 30, and 30. If we add them, we get 125.
anonymous
  • anonymous
Ty for breaking it down...you saved me alot of time.
anonymous
  • anonymous
theres another one just like that with 3 triangles
anonymous
  • anonymous
Did i do this right so far?
1 Attachment
KingGeorge
  • KingGeorge
That looks correct to me.
anonymous
  • anonymous
ok so now all i have to do is add them all together correct?
KingGeorge
  • KingGeorge
Correct.
anonymous
  • anonymous
Ok.
katielong
  • katielong
|dw:1334855745714:dw| here you see i worked out all of the sides by doing some halving. so... you can see the top triangles are 4cmx7.5cm to find the area times them which equals 30 if you notice, it now needs halving but 30 is the equivilant of the area of two of those triangles so you dont need to half it. its the same with the 13cmx5cm triangle 13x5=65 then you need to finally find the area of the last one... which is the same as the first... so to find the area of the shape you need to do... 30+65+30=........answer.....=125!!!!!!!!! hope it helped?
anonymous
  • anonymous
i got 22.
anonymous
  • anonymous
Ty @katielong
katielong
  • katielong
no probss =) do you understand it??
anonymous
  • anonymous
yes.
anonymous
  • anonymous
|dw:1334856366881:dw|
anonymous
  • anonymous
@KingGeorge & @katielong
KingGeorge
  • KingGeorge
You're very welcome.
katielong
  • katielong
youre welcommeeeee =)

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