A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
f(x)=tan(x)
Find the limit as x approaches pi/2 from the negative and positive sides then find the limit as x approaches 0.
Help please!! :(
anonymous
 4 years ago
f(x)=tan(x) Find the limit as x approaches pi/2 from the negative and positive sides then find the limit as x approaches 0. Help please!! :(

This Question is Open

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think if you make a graphic you can solve the problem more easy , substitute the values of x and make the graphic.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Here how you can proceed,tanx at the positive side of pi/2 (right hand) takes nonpositive values and at the left side it takes nonnegative values now for limit to exist limit from tight and left must exist and be equal to each other so only possible choice in this case is both to be 0 however as one approaches to pi/2 sinx increase and cosx decreases leading to tanx become larger over any bounds so at left side tangent goes to infinity on the posive side and at right limit tangent goes to inifinity at the negative side so limit does not exist

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\tan x=\sin x/\cos x\]\[\cos (pi/2) = 0\] so as tan x approaches \[pi/2\] from right or left it goes to infinity as cos x gets smaller and smaller.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0look at the graph of tanx.... and see where does it tends when it is approaching pi/2... so it is infinity...from both sides...!!!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.