anonymous
  • anonymous
Are there any common tricks with inverse and direct variation? Examples would be very helpful for me.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
Let's say I was able to measure productivity \(w\), profit \(p\), and cost of materials \(c\) quantitatively. A reasonable model for an explicitly simple system would be:\[p=\frac{w}{c}\]Now, which variables vary directly, and which vary indirectly? Tell me what you think. Even if it's wrong.
anonymous
  • anonymous
Vary Directly-c Vary indirecly-w I am not sure.
anonymous
  • anonymous
Alright, so as \(p\) increases in\[p=\frac{w}{c}\]either \(w\) is getting higher, or \(c\) is getting lower, or both. For instance, if \(p=2\), \(w=6\), and \(c=3\), what are possible values of \(w,c\) if I increased \(p=4\)?

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anonymous
  • anonymous
6=36/6
anonymous
  • anonymous
Very good. You noticed that \(w\) increased (by a larger margin than \(c\))? Now, returning to the previous question, what if I reduced \(p=1\)?
anonymous
  • anonymous
if reduced by one then 1=infinite no of solutions?
anonymous
  • anonymous
Yes, there are an infinite number of solutions. I'm asking what are possible solutions.
anonymous
  • anonymous
like 6/6
anonymous
  • anonymous
Yup. Noticed now how \(c\) increased by a larger margin than \(w\)? So what do you think: does \(p\) increase and decrease directly or inversely with \(c\) and \(w\)?
anonymous
  • anonymous
inversely
anonymous
  • anonymous
Not both. Which to which? If I increase \(p\), \(w\) generally grows larger and \(c\) smaller, so the number \(w/c\) is larger. If I decrease \(p\), \(w\) generally grows smaller, and \(c\) larger, so \(w/c\) grows smaller. Do you understand?
anonymous
  • anonymous
Yeah! Thanks a lot so much. :-) Now I understand
anonymous
  • anonymous
So, final test. Does \(c\) vary inversely or directly with \(p\)? What about \(w\)?
anonymous
  • anonymous
Hey, I invested time into this. I want to see you actually learned something. :P
anonymous
  • anonymous
Just, Hold on a bit I will get to it...
anonymous
  • anonymous
@myininaya I know you're an actual teacher, you might be better here. :P
anonymous
  • anonymous
inversely
anonymous
  • anonymous
Am I right?

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