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jaersyn Group TitleBest ResponseYou've already chosen the best response.1
1/(cosx/sinx)  (1/cosx)/(1/sinx) = (sinx/cosx)  (sinx/cosx) = 0
 2 years ago

kaisan Group TitleBest ResponseYou've already chosen the best response.0
@jaersyn how u get (sinx/cosx)(sinx/cosx)?
 2 years ago

jaersyn Group TitleBest ResponseYou've already chosen the best response.1
cotx = cosx/sinx secx = 1/cosx cscx = 1/sinx
 2 years ago

jaersyn Group TitleBest ResponseYou've already chosen the best response.1
also tanx = sinx/cosx
 2 years ago

kaisan Group TitleBest ResponseYou've already chosen the best response.0
@jaersyn dw:1334812473900:dw so it look like this? then what did u do from there to get (sinx/cosx)(sinx/cosx)?
 2 years ago

jaersyn Group TitleBest ResponseYou've already chosen the best response.1
if you multiply the top and bottom by the reciprocal you can get rid of the denominators
 2 years ago

jaersyn Group TitleBest ResponseYou've already chosen the best response.1
dw:1334802046545:dw
 2 years ago

kaisan Group TitleBest ResponseYou've already chosen the best response.0
i got it! thank you!
 2 years ago
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