kaisan
simplify the expression:
1/cotxsecx/cscx



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jaersyn
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1/(cosx/sinx)  (1/cosx)/(1/sinx) =
(sinx/cosx)  (sinx/cosx) = 0

kaisan
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@jaersyn how u get (sinx/cosx)(sinx/cosx)?

jaersyn
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cotx = cosx/sinx
secx = 1/cosx
cscx = 1/sinx

jaersyn
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also tanx = sinx/cosx

kaisan
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@jaersyn dw:1334812473900:dw so it look like this? then what did u do from there to get (sinx/cosx)(sinx/cosx)?

jaersyn
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if you multiply the top and bottom by the reciprocal you can get rid of the denominators

jaersyn
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dw:1334802046545:dw

kaisan
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i got it! thank you!