kaisan
simplify the expression:
(sinx-1)(tanx+secx)
help pretty please
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kaisan
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?
kaisan
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should i convert the tan and sec to sin and cos?
jaersyn
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yes
Argonx16
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Always start by breaking up Tangent/Cosecant/Secant/Cotangent into their constituents.
lgbasallote
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ahh..an interesting question >:))
bmp
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That simplifies to -cosx, right? If someone could check :-).
kaisan
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i'm confused on what to do next >.<' i got this: |dw:1334814256375:dw|
Argonx16
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You're pretty close. Remember that Secant is 1/Cosine, not 1/Sine.
jaersyn
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that would make the problem infinitely easier haha
kaisan
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|dw:1334814461856:dw| so then so i just put them together?
Argonx16
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Given
\[(sin(x-1))(tanx+secx)\]
Simplify RHS
\[(\sin(x-1)) * ((sinx/cosx)+(1/cosx))\]
Which if you add the RHS together you should get
\[(\sin(x-1))(1+sinx/cosx)\]
And then you multiply.
kaisan
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i multiply straight across?
lgbasallote
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i think it was just
\[\large sinx - 1\]right?
kaisan
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the first part is
lgbasallote
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so it'll be
\[\large \mathbf{(sinx-1)*\frac{sinx+1}{cosx}}\]
\[\large \mathbf{\frac{(sinx-1)(sinx + 1)}{cosx}}\]
lgbasallote
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i'll let you guys do the rest :P
Hint: difference of two squares
Argonx16
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Oooh. I see what I did. That makes sense :D
kaisan
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i got it ty ^^
kaisan
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no wait its supposed to be negative but i got positive