anonymous
  • anonymous
simplify the expression: (sinx-1)(tanx+secx) help pretty please
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
?
anonymous
  • anonymous
should i convert the tan and sec to sin and cos?
anonymous
  • anonymous
yes

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anonymous
  • anonymous
Always start by breaking up Tangent/Cosecant/Secant/Cotangent into their constituents.
lgbasallote
  • lgbasallote
ahh..an interesting question >:))
anonymous
  • anonymous
That simplifies to -cosx, right? If someone could check :-).
anonymous
  • anonymous
i'm confused on what to do next >.<' i got this: |dw:1334814256375:dw|
anonymous
  • anonymous
You're pretty close. Remember that Secant is 1/Cosine, not 1/Sine.
anonymous
  • anonymous
that would make the problem infinitely easier haha
anonymous
  • anonymous
|dw:1334814461856:dw| so then so i just put them together?
anonymous
  • anonymous
Given \[(sin(x-1))(tanx+secx)\] Simplify RHS \[(\sin(x-1)) * ((sinx/cosx)+(1/cosx))\] Which if you add the RHS together you should get \[(\sin(x-1))(1+sinx/cosx)\] And then you multiply.
anonymous
  • anonymous
i multiply straight across?
lgbasallote
  • lgbasallote
i think it was just \[\large sinx - 1\]right?
anonymous
  • anonymous
the first part is
lgbasallote
  • lgbasallote
so it'll be \[\large \mathbf{(sinx-1)*\frac{sinx+1}{cosx}}\] \[\large \mathbf{\frac{(sinx-1)(sinx + 1)}{cosx}}\]
lgbasallote
  • lgbasallote
i'll let you guys do the rest :P Hint: difference of two squares
anonymous
  • anonymous
Oooh. I see what I did. That makes sense :D
anonymous
  • anonymous
i got it ty ^^
anonymous
  • anonymous
no wait its supposed to be negative but i got positive

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