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simplify the expression: (sinx-1)(tanx+secx) help pretty please

Mathematics
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should i convert the tan and sec to sin and cos?
yes

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Other answers:

Always start by breaking up Tangent/Cosecant/Secant/Cotangent into their constituents.
ahh..an interesting question >:))
That simplifies to -cosx, right? If someone could check :-).
i'm confused on what to do next >.<' i got this: |dw:1334814256375:dw|
You're pretty close. Remember that Secant is 1/Cosine, not 1/Sine.
that would make the problem infinitely easier haha
|dw:1334814461856:dw| so then so i just put them together?
Given \[(sin(x-1))(tanx+secx)\] Simplify RHS \[(\sin(x-1)) * ((sinx/cosx)+(1/cosx))\] Which if you add the RHS together you should get \[(\sin(x-1))(1+sinx/cosx)\] And then you multiply.
i multiply straight across?
i think it was just \[\large sinx - 1\]right?
the first part is
so it'll be \[\large \mathbf{(sinx-1)*\frac{sinx+1}{cosx}}\] \[\large \mathbf{\frac{(sinx-1)(sinx + 1)}{cosx}}\]
i'll let you guys do the rest :P Hint: difference of two squares
Oooh. I see what I did. That makes sense :D
i got it ty ^^
no wait its supposed to be negative but i got positive

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