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kaisan
Group Title
simplify the expression:
(sinx1)(tanx+secx)
help pretty please
 2 years ago
 2 years ago
kaisan Group Title
simplify the expression: (sinx1)(tanx+secx) help pretty please
 2 years ago
 2 years ago

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kaisan Group TitleBest ResponseYou've already chosen the best response.0
should i convert the tan and sec to sin and cos?
 2 years ago

Argonx16 Group TitleBest ResponseYou've already chosen the best response.0
Always start by breaking up Tangent/Cosecant/Secant/Cotangent into their constituents.
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
ahh..an interesting question >:))
 2 years ago

bmp Group TitleBest ResponseYou've already chosen the best response.0
That simplifies to cosx, right? If someone could check :).
 2 years ago

kaisan Group TitleBest ResponseYou've already chosen the best response.0
i'm confused on what to do next >.<' i got this: dw:1334814256375:dw
 2 years ago

Argonx16 Group TitleBest ResponseYou've already chosen the best response.0
You're pretty close. Remember that Secant is 1/Cosine, not 1/Sine.
 2 years ago

jaersyn Group TitleBest ResponseYou've already chosen the best response.1
that would make the problem infinitely easier haha
 2 years ago

kaisan Group TitleBest ResponseYou've already chosen the best response.0
dw:1334814461856:dw so then so i just put them together?
 2 years ago

Argonx16 Group TitleBest ResponseYou've already chosen the best response.0
Given \[(sin(x1))(tanx+secx)\] Simplify RHS \[(\sin(x1)) * ((sinx/cosx)+(1/cosx))\] Which if you add the RHS together you should get \[(\sin(x1))(1+sinx/cosx)\] And then you multiply.
 2 years ago

kaisan Group TitleBest ResponseYou've already chosen the best response.0
i multiply straight across?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
i think it was just \[\large sinx  1\]right?
 2 years ago

kaisan Group TitleBest ResponseYou've already chosen the best response.0
the first part is
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
so it'll be \[\large \mathbf{(sinx1)*\frac{sinx+1}{cosx}}\] \[\large \mathbf{\frac{(sinx1)(sinx + 1)}{cosx}}\]
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
i'll let you guys do the rest :P Hint: difference of two squares
 2 years ago

Argonx16 Group TitleBest ResponseYou've already chosen the best response.0
Oooh. I see what I did. That makes sense :D
 2 years ago

kaisan Group TitleBest ResponseYou've already chosen the best response.0
i got it ty ^^
 2 years ago

kaisan Group TitleBest ResponseYou've already chosen the best response.0
no wait its supposed to be negative but i got positive
 2 years ago
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