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kaisan
 2 years ago
Best ResponseYou've already chosen the best response.0should i convert the tan and sec to sin and cos?

Argonx16
 2 years ago
Best ResponseYou've already chosen the best response.0Always start by breaking up Tangent/Cosecant/Secant/Cotangent into their constituents.

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1ahh..an interesting question >:))

bmp
 2 years ago
Best ResponseYou've already chosen the best response.0That simplifies to cosx, right? If someone could check :).

kaisan
 2 years ago
Best ResponseYou've already chosen the best response.0i'm confused on what to do next >.<' i got this: dw:1334814256375:dw

Argonx16
 2 years ago
Best ResponseYou've already chosen the best response.0You're pretty close. Remember that Secant is 1/Cosine, not 1/Sine.

jaersyn
 2 years ago
Best ResponseYou've already chosen the best response.1that would make the problem infinitely easier haha

kaisan
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1334814461856:dw so then so i just put them together?

Argonx16
 2 years ago
Best ResponseYou've already chosen the best response.0Given \[(sin(x1))(tanx+secx)\] Simplify RHS \[(\sin(x1)) * ((sinx/cosx)+(1/cosx))\] Which if you add the RHS together you should get \[(\sin(x1))(1+sinx/cosx)\] And then you multiply.

kaisan
 2 years ago
Best ResponseYou've already chosen the best response.0i multiply straight across?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1i think it was just \[\large sinx  1\]right?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1so it'll be \[\large \mathbf{(sinx1)*\frac{sinx+1}{cosx}}\] \[\large \mathbf{\frac{(sinx1)(sinx + 1)}{cosx}}\]

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.1i'll let you guys do the rest :P Hint: difference of two squares

Argonx16
 2 years ago
Best ResponseYou've already chosen the best response.0Oooh. I see what I did. That makes sense :D

kaisan
 2 years ago
Best ResponseYou've already chosen the best response.0no wait its supposed to be negative but i got positive
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