A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Two cab companies operate in River City, the blue and the green, named according to the colors of the cabs they run. 85% of the cabs in River City are blue cabs and 15% are green cabs. a cab was involved in a hit and run accident at night. an eyewitness later identified the cab as green. the court tested the witness's ability to distinguish between blue and green cabs under nightitme visibiltiy conditions. it found the witness was able to identify each color correctly 80% of the time, but he confused it with the other color 20% of the time. What is the probability that the cab in the accident
anonymous
 4 years ago
Two cab companies operate in River City, the blue and the green, named according to the colors of the cabs they run. 85% of the cabs in River City are blue cabs and 15% are green cabs. a cab was involved in a hit and run accident at night. an eyewitness later identified the cab as green. the court tested the witness's ability to distinguish between blue and green cabs under nightitme visibiltiy conditions. it found the witness was able to identify each color correctly 80% of the time, but he confused it with the other color 20% of the time. What is the probability that the cab in the accident

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0really was green, as the witness claimed it was?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is it 80% times 15% ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Hmm. so basically we need to find the probability of 'truth' right. Since the witness claims that the was was green, he following events may have happened > 'A'=The cab was actually green & the witness spotted it correctly> 0.15 times 0.80 > 'B'=The cab was blue actually and the witness spotted it wrongly> 0.85 times 0.20 The sum of Ps of the two cases = 0.12 + 0.17 P of favourable condition 'A' > 0.12

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes that is the absolute P for it, but you need to find the conditional probability.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0whats that? how do you go about finding it?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I just provided you with the sum of the conditions. and there is that favorable condition too. so P = (favorable probability)/(Total probability) = 0.12/(0.12+0.17) = 0.12/0.29

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhhhhh. thanks dude.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No probs, hope you understood the concepts there.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.