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set 2sin(x^2)=0

Wait, over an interval -_-

Ignore the interval, and just solve that trig equation.

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i know that the answer for part "a" is

square(pi)

square or sqrt?

i dont know how to do part b

sqrt

up to 3

a)\[2*\sin(2*x)=0\rightarrow x=k*pi/2\]
In this interval x=pi/2

Do you understand a though?

well i got x= |dw:1334814197335:dw|

|dw:1334814169184:dw|

and is the right answer

|dw:1334814236680:dw|

Naturally, sqrt pi would be the largest value up to 3, because it squares out to pi.

the equation is f(x) = 2sin(x^2)

sorry about that

\[F(x)=-\cos(2*x)+K'\]
\[F(1)=-\cos(2*1)+K'=9\]

I know - That is sin x

but, sin x^2 is similar to the graph in that it has its highest values at sqrtpi

sqrt(pi) is the right answer for part a is marking it right

the part that i dont get how to do is part b

Yes. Can you tell me what calc course you are enrolled in?

calculus I

Alright, give me a second.

2sin(x^2) = 0
x^2 = pi
x = sqrt(pi)

thats how i got my answer

Have you learned how to approximate integrals?

kinda

thats what we are learning

What's it called?

antiderivatives

No, what kind of approximations have you learned?

I just figured out how I can solve the problem.

Here's the graph, btw

i dont know

http://www.wolframalpha.com/input/?i=integrate+2+sin%28x%5E2%29

the tittle of this chapter is antiderivatives

so how do i do part b?

I'm thinking ;)

Have you learned trapozoidal approximation?

no

I also have a question for part b... help us figure this out plz

http://www.wolframalpha.com/input/?i=+2+sin%28x%5E2%29

Alright. that is the graph of f(x)=2 sin(x^2) right?

Notice how the waves become wider and wider close to 0.

after that, they become thinner and thinner.

Now, give me a second to explain something.

Let me get htis plot into mathematica, and show you what I'm talking about.

Ok. The area of a>b>c>d Tell me if you understand.

yes i do

So, because of this, we know that from 0 to 3, the area enclosed in a is the greatest

yes

So we are essentially looking for the area there.

@FoolForMath , I give up/

;/

I can give you the answer though, me being a cheater cheater.

what's the answer?

i wish i could do this math. -_-

Give me a second.

I'm going to numerically evaluate the integral with wolfram Mathematica

1.78966

@lgbasallote , here you go.

the answer is wrong

WHAT?

Try the square root of pi then.

as the answer?

Yes.

wrong

btw, try 1.790 if you haven't already.

i did its wrong

Ahem.

;(

lol why call me =)) i only know algebra :P i dont like these stuffs

:((

Wrong, call >.<

http://www.wolframalpha.com/input/?i=integral%5B2+sin%28x%5E2%29%2C%7Bx%2C0%2Csqrt%28pi%29%7D%5D

Got any more info about what you are learning right now?

If I used the methods they gave, I might just get the answer they are looking for.

i got the answer is y = 10.16912...

That's th correct answer?

|dw:1334818371099:dw|

yes

Well, then I'm completely useless.

10.170 is the answer

Nice job.

thanks anyways

how old are you?

15

I'm still not sure how I missed that problem so badly. :/

15? really?

yes dumbcow

I believe graph would go like this. (the pitch decreasing with increase in x)
|dw:1334819574505:dw|

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