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Aadarsh

The wavelength of light in two liquids "x" and "y" is 3500 angstroms and 7000 angstroms respectively. Find the critical angle of "x" relative to "y".

  • one year ago
  • one year ago

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  1. apoorvk
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    You know the wavelengths of the red and violet, you can find relative refractive indices for two lights (by assuming yellow light as a constant). Then you can use the formula for critical angle, since you already have the refractive indices. (just calculate everything in terms of an assumed constant 'x', and in the end you'll find that the 'x' gets cancelled)

    • one year ago
  2. Aadarsh
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    Can you expalin the steps please?

    • one year ago
  3. Aadarsh
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    @Ishaan94 please try.

    • one year ago
  4. Ishaan94
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    You need to tell me what's critical angle?

    • one year ago
  5. Aadarsh
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    The angle of incidence for which the angle of refraction is 90 degrees is called "critical angle".

    • one year ago
  6. Ishaan94
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    Oh hmm, so relative reflective index must be \(\large n = \frac{\lambda_x}{\lambda_y}\), right?

    • one year ago
  7. Aadarsh
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    ooooooooh Yeah!!!!

    • one year ago
  8. Aadarsh
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    But how?

    • one year ago
  9. Ishaan94
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    |dw:1334817280641:dw|\[n = \frac{\sin\theta_i}{\sin \theta_r}\]

    • one year ago
  10. Ishaan94
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    \(\theta_r \to 90 \implies \sin\theta_r \to1\)\[\implies n = \sin\theta_i\]

    • one year ago
  11. Ishaan94
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    Wow. Nice. Thankyou Aadarsh for posting it.

    • one year ago
  12. Aadarsh
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    Yeah. Got it. So, it is: \[\sin 30 = 3500/7000 = 1/2 \] So, answer = sin 30 degrees, rite?

    • one year ago
  13. Ishaan94
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    Yes, It is.

    • one year ago
  14. Aadarsh
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    Thanks Bhaiiiiiiiiijan!!!

    • one year ago
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