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Aadarsh
The wavelength of light in two liquids "x" and "y" is 3500 angstroms and 7000 angstroms respectively. Find the critical angle of "x" relative to "y".
You know the wavelengths of the red and violet, you can find relative refractive indices for two lights (by assuming yellow light as a constant). Then you can use the formula for critical angle, since you already have the refractive indices. (just calculate everything in terms of an assumed constant 'x', and in the end you'll find that the 'x' gets cancelled)
Can you expalin the steps please?
You need to tell me what's critical angle?
The angle of incidence for which the angle of refraction is 90 degrees is called "critical angle".
Oh hmm, so relative reflective index must be \(\large n = \frac{\lambda_x}{\lambda_y}\), right?
|dw:1334817280641:dw|\[n = \frac{\sin\theta_i}{\sin \theta_r}\]
\(\theta_r \to 90 \implies \sin\theta_r \to1\)\[\implies n = \sin\theta_i\]
Wow. Nice. Thankyou Aadarsh for posting it.
Yeah. Got it. So, it is: \[\sin 30 = 3500/7000 = 1/2 \] So, answer = sin 30 degrees, rite?
Thanks Bhaiiiiiiiiijan!!!