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Aadarsh Group Title

The wavelength of light in two liquids "x" and "y" is 3500 angstroms and 7000 angstroms respectively. Find the critical angle of "x" relative to "y".

  • 2 years ago
  • 2 years ago

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  1. apoorvk Group Title
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    You know the wavelengths of the red and violet, you can find relative refractive indices for two lights (by assuming yellow light as a constant). Then you can use the formula for critical angle, since you already have the refractive indices. (just calculate everything in terms of an assumed constant 'x', and in the end you'll find that the 'x' gets cancelled)

    • 2 years ago
  2. Aadarsh Group Title
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    Can you expalin the steps please?

    • 2 years ago
  3. Aadarsh Group Title
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    @Ishaan94 please try.

    • 2 years ago
  4. Ishaan94 Group Title
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    You need to tell me what's critical angle?

    • 2 years ago
  5. Aadarsh Group Title
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    The angle of incidence for which the angle of refraction is 90 degrees is called "critical angle".

    • 2 years ago
  6. Ishaan94 Group Title
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    Oh hmm, so relative reflective index must be \(\large n = \frac{\lambda_x}{\lambda_y}\), right?

    • 2 years ago
  7. Aadarsh Group Title
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    ooooooooh Yeah!!!!

    • 2 years ago
  8. Aadarsh Group Title
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    But how?

    • 2 years ago
  9. Ishaan94 Group Title
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    |dw:1334817280641:dw|\[n = \frac{\sin\theta_i}{\sin \theta_r}\]

    • 2 years ago
  10. Ishaan94 Group Title
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    \(\theta_r \to 90 \implies \sin\theta_r \to1\)\[\implies n = \sin\theta_i\]

    • 2 years ago
  11. Ishaan94 Group Title
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    Wow. Nice. Thankyou Aadarsh for posting it.

    • 2 years ago
  12. Aadarsh Group Title
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    Yeah. Got it. So, it is: \[\sin 30 = 3500/7000 = 1/2 \] So, answer = sin 30 degrees, rite?

    • 2 years ago
  13. Ishaan94 Group Title
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    Yes, It is.

    • 2 years ago
  14. Aadarsh Group Title
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    Thanks Bhaiiiiiiiiijan!!!

    • 2 years ago
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